I would say it’s 4
Nsjdksks
<span>The molar volume of ammonia at standard temperature and pressure (STP) is 22.4L. This is the standard molar volume of any gas at these conditions.</span>
Answer:
0.683 moles of the gas are required
Explanation:
Avogadro's law relates the moles of a gas with its volume. The volume of a gas is directely proportional to its moles when temperature and pressure of the gas remains constant. The law is:
V₁n₂ = V₂n₁
<em>Where V is volume and n are moles of 1, initial state and 2, final state of the gas.</em>
<em />
Computing the values of the problem:
1.50Ln₂ = 5L*0.205mol
n₂ = 0.683 moles of the gas are required
<em />
Answer:
A stir bar consists of a magnetic bar used to agitate a liquid mixture or solution
Explanation:
Answer:
Ksp = 7.4x10⁻⁷
Explanation:
Molar solubility of a substance is defined as the amount of moles of that can be dissolved per liter of solution.
Ksp of Zn(OH)₂ is:
Zn(OH)₂(s) ⇄ Zn²⁺ + 2OH⁻
Ksp = [Zn²⁺] [OH⁻]²
And the molar solubility, X, is:
Zn(OH)₂(s) ⇄ Zn²⁺ + 2OH⁻
⇄ X + 2X
<em>Because X are moles of substance dissolved.</em>
<em>Ksp = </em>[X] [2X]²
Ksp = 4X³
As molar solubility, X, is 5.7x10⁻³mol/L:
Ksp = 4X³
Ksp = 4 (5.7x10⁻³mol/L)³
<h3>Ksp = 7.4x10⁻⁷</h3>
