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Veseljchak [2.6K]
2 years ago
14

Provide a method for separating the mixtures of two or three compounds, dissolved in a solvent diethyl ether. In each case one o

f the components will be a neutral compound. You should give your answer in the form of a flow chart (see Section 12.12). a. Benzophenone and tributylamine b. 4-Bromoaniline, 3-nitrobenzoic acid, and benzoin c. Fluorenone, octanoic acid, and dicyclohexylamine d. 1-Hexanol and 4-bromoaniline
Chemistry
1 answer:
lys-0071 [83]2 years ago
5 0

Answer:

The complete aerobic oxidation of glucose is coupled to the synthesis of as many as 36 molecules of ATP

Explanation:

Glycolysis, the initial stage of glucose metabolism, takes place in the cytosol and does not involve molecular O2. It produces a small amount of ATP and the three-carbon compound pyruvate. In aerobic cells, pyruvate formed in glycolysis is transported into the mitochondria, where it is oxidized by O2 to CO2. Via chemiosmotic coupling, the oxidation of pyruvate in the mitochondria generates the bulk of the ATP produced during the conversion of glucose to CO2. The biochemical pathways that oxidize glucose and fatty acids to CO2 and H2O.

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Some soils, like clay, hold water tightly. Other soils, like sand, let the water run through. What property of soils is MOST IMP
RoseWind [281]
Most likely the second one (sand letting water run through it) because if you are trying to determine how what moves through soil You would want the one the one that can do that:)
8 0
3 years ago
Given the following equation: 2h20=2h2+02 how many grams of o2 are produced if 3.6 grams of h20 react?
inn [45]

Answer:

3.2 g O₂

Explanation:

To find the mass of O₂, you need to (1) convert grams H₂O to moles H₂O (via molar mass), then (2) convert moles H₂O to moles O₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles O₂ to grams O₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to reflect the sig figs of the given value (3.6 g).

Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol

Molar Mass (H₂O): 18.014 g/mol

2 H₂O -----> 2 H₂ + 1 O₂

Molar Mass (O₂): 2(15.998 g/mol)

Molar Mass (O₂): 31.996 g/mol

3.6 g H₂O         1 mole               1 mole O₂           31.996 g
----------------  x  ---------------  x  ---------------------  x  ---------------  = 3.2 g O₂
                         18.014 g          2 moles H₂O          1 mole

3 0
1 year ago
If the limiting reactant in a chemical reaction is impure, what will happen to the percentage yield of the product?
Elanso [62]

Answer:

it may also become impure,I think.

6 0
2 years ago
Calculate weight of anhydrous compound from remains upon dehydration of 2g copper sulphate pentahydrate
Greeley [361]

Answer:

1.28 g

Explanation:

Mass of anhydrous compound/molar mass of anhydrous compound = mass of hydrated compound/ molar mass of hydrated compound

Mass of anhydrous compound = ?

Mass of hydrated compound = 2g

Molar mass of anhydrous compound= 160 g/mol

Molar mass of hydrated compound = 250 g/mol

x/160 = 2/250

250x = 2 ×160

x= 2 × 160/250

x= 1.28 g

4 0
2 years ago
2. A sample of neon gas has a volume of 87.6 L at STP. How many moles are present?
PSYCHO15rus [73]

Answer:

                      3.91 moles of Neon

Explanation:

According to Avogadro's Law, same volume of any gas at standard temperature (273.15 K or O °C) and pressure (1 atm) will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).

Data Given:

                 n = moles = <u>???</u>

                 V = Volume = 87.6 L

Solution:

               As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain....

                          = ( 1 mole × 87.6 L) ÷ 22.4 L

                          = 3.91 moles

<h3>2nd Method:</h3>

                     Assuming that the gas is acting ideally, hence, applying ideal gas equation.

                              P V  =  n R T      ∴  R  =  0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹

Solving for n,

                              n  =  P V / R T

Putting values,

                              n  =  (1 atm × 87.6 L)/(0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹ × 273.15K)

                              n  =  3.91 moles

Result:

          87.6 L of Neon gas will contain 3.91 moles at standard temperature and pressure.

7 0
2 years ago
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