Answer:
The average atomic weight = 121.7598 amu
Explanation:
The average atomic weight of natural occurring antimony can be calculated as follows :
To calculate the average atomic mass the percentage abundance must be converted to decimal.
121 Sb has a percentage abundance of 57.21%, the decimal format will be
57.21/100 = 0.5721 . The value is the fractional abundance of 121 Sb .
123 Sb has a percentage abundance of 42.79%, the decimal format will be
42.79/100 = 0.4279. The value is the fractional abundance of 123 Sb .
Next step is multiplying the fractional abundance to it masses
121 Sb = 0.5721 × 120.904 = 69.169178400
123 Sb = 0.4279 × 122.904 = 52.590621600
The final step is adding the value to get the average atomic weight.
69.169178400 + 52.590621600 = 121.7598 amu
Answer:Gained, Lost , Shared
Explanation:
The oxidation state tells you how many electrons an atom has GAINED.................. , LOST....................... , or SHARED........................ , in forming a compound.
Oxidation state is defined as the the total number of electrons that an atom gains or loses when forming a chemical bond with another atom.
----To form an ionic bond for example in NaCl, Na, with 11 electrons and one valence electron in its outermost shell donates or lose that valence electron to Chlorine with 17 electron and 7 in its outermost shell. Therefore Sodium, Na acquires the +1 oxidaton state to become stable and Chlorine acquires the -1 oxidation state to become stable forming the NaCl compound.
To form a covalent compound, There must be sharing of electrons between atoms.For example, in PCl3, The phosphorous atom with atomic number 15 shares its three unpaired electrons with the single valence electrons of three chlorine atoms. making the four molecules to attain stability with Phosphorous having +3 and the chlorine atoms having -1 oxidation states
The given question tells you that a certain piece of wire has a mass = 2.0 g per meter
That means that if you consider a piece of wire that is 1 m in length, its mass will be equal to 2.00 g .
According to question,
Now, you know that
1 m = 100 cm
Mass of 2.00 g of copper will correspond to a wire that is a 100 cm long.
This implies that 0.28 gof copper will correspond to a wire that is
0.28 g * 100 cm / 2.0 g = 14 cm long
Hence, 14 cm of the wire would be needed to provide 0.28 g of copper.
Properties of Copper :
High conductivity and ductility.
Non magnetic.
To know more about Copper here:
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Hello! Let me try to answer this :)
Thanks and please correct if there are any mistakes ^ ^
Answer:
Explanation: 1Pa 1 N/m^2. p = F/A and A = F/p = 300N /35 Pa = 8.57 m^2
