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hichkok12 [17]
3 years ago
14

Metallic element are _____ (conductors or non-conductors), because ________. Nonmetallic elements are generally ____ (conductors

or non-conductors). Pure solidionic compounds are ______ (conductors or non-conductors), because_____, but molten ionic compounds are ______ (conductors or non-conductors), because _______.Pure molecular compounds are generally _____ (conductors or non-conductors). A concentrated aqueous solution of a strong acid such as HCl is a (conductor ornon-conductor), because _____. As the concentration of the HCl solution decreases, the conductance ____ (decreases or increases), because _____. Mixtures of metalsare _____ (conductors or non-conductors), because ______.
Chemistry
1 answer:
STatiana [176]3 years ago
5 0

Answer:

Metallic element are conductors, because it shows north and south pole. Nonmetallic elements are generally non-conductors. Pure solidionic compounds are conductors, because they are found in solid state, but molten ionic compounds are conductors or non-conductors), because ionic component show property of metal.Pure molecular compounds are generally (conductors or non-conductors). A concentrated aqueous solution of a strong acid such as HCl is a (conductor ornon-conductor), because. As the concentration of the HCl solution decreases, the conductance increases), because Mixtures of metalsare non-conductors), because it doesn't show property of metal.

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There are no insoluble precipitate forms.

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There are the insoluble precipitates of CaCo_{3}  forms.

c) Li_{2}S and MnBr_{2} :

There are the insoluble precipitates of MnS  forms.

d) Ba(No_{3} )_{2} and Ag_{2} So_{4} :                        

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e) Rb_{2}Co_{3} and NaCl:

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Explanation:

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Solubility rule suggests:- K_{2} S ⇒ soluble, NH_{4} Cl ⇒ soluble.

                                          KCl ⇒ soluble, (NH_{4})_{2} S  ⇒ soluble.

There are no insoluble precipitate forms.

b)

Solubility rule suggests:- Ca Cl_{2} ⇒ soluble, (NH_{4} )_{2} Co_{3} ⇒ soluble.

                                        CaCo_{3} ⇒ insoluble, NH_{4} Cl  ⇒ soluble.

There are the insoluble precipitates of CaCo_{3}  forms.

c)

Solubility rule suggests:- Li_{2}S ⇒ soluble, MnBr_{2} ⇒ soluble.

                                        LiBr ⇒ soluble, MnS  ⇒ insoluble.

There are the insoluble precipitates of MnS  forms.

d)

Solubility rule suggests:- Ba(No_{3} )_{2} ⇒ soluble, Ag_{2} So_{4} ⇒insoluble.

                                     

As Ag_{2} So_{4} is insoluble, therefore no precipitate forms.

e)

Solubility rule suggests:- Rb_{2}Co_{3} ⇒ soluble, NaCl ⇒ soluble.

                                        RbCl ⇒ soluble, Na_{2} Co_{3}  ⇒ soluble.

There are no insoluble precipitates forms.

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