Answer:
Partial pressure of
in the gas was 733 torr and mass of
in the sample was 2.12 g.
Explanation:
a) Total pressure of gas = (partial pressure of water vapour)+(partial pressure of
)
Here partial pressure of water vapour is 21 torr and total pressure of gas is 754 torr.
So, partial pressure of
= (total pressure of gas)-(partial pressure of water vapour) = (754 torr) - (21 torr) = 733 torr
b) Lets assume that
behaves ideally. Hence-
PV=nRT
where P is pressure of
, V is volume of
, n is number of moles of
, R is gas constant and T is temperature in kelvin
here P = 733 torr =
= 0.9646 atm
V = 0.65 L, R = 0.082 L.atm/(mol.K), T=(273+22)K = 295 K
So, 
= 
= 0.0259 moles
As 3 moles of
are produced from 2 moles of
therefore 0.0259 moles of
are produced from
moles or 0.0173 moles of
.
Molar mass of
= 122.55 g
So mass of
in sample = 
= 2.12 g
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Explanation:
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