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2 years ago

PLEASE HELP ONLY ONE QUESTION

Chemistry

2 answers:

rosijanka [135]2 years ago

7 0

When reactant particles collide with proper energy and proper orientation

ad-work [718]2 years ago

6 0

A chemical reaction occurs when reactant particles collide with proper energy and proper orientation.

Hope this helps! Have a great day! <3

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The decayed organic material that gives soil its dark brown or black color is called

sergiy2304 [10]

Option B. Humus. Its dark color is due to the high content of carbon.

3 0

3 years ago

Read 2 more answers

If one gram of sulphur dioxide contains x molecules what will be the number of molecules in 1g of methane

evablogger [386]

The ratio of molecules in sulphur dioxide and methane will be the same as the ratio of their moles. So, first of all we should find out the number of moles of sulphur dioxide in 1 gram of sulphur dioxide in 1 gram of sulphur dioxide, and the number of moles of methane in 1 gram of methane. This can be done as follows :

(i) The molecular formula of sulphur dioxide is $SO_{2}$

So, $1$ mole of $SO_{2}$ = $Mass$ $of$ $2'O'$

$=32+2*16$

$= 64$ grams

Now, $64g$ of sulphur dioxide $= 1$ mole

So, $1g$ of sulphur dioxide = $\frac{1}{64}$ mole

Thus, we have $\frac{1}{64}$ mole of sulphur dioxide and it contains molecules in it. Now, since equal moles of all the substance contain equal number of molecules, therefore, $\frac{1}{64}$ mole of methane will also contain x molecules of methane.

(ii) Molecular formula of methan is $CH_{4}$

So, 1 mole of $CH_{4}$ = Mass of C + Mass of 4 H

$=12+4*12$

Now, 16g of methane = 1 mole

So, 1 g of mathane = $\frac{1}{16}$ mole

We know that:

$\frac{1}{64}$ mole of methane contains = x molecules

So, $\frac{1}{16}$ mole of contains will contain = $\frac{x*64}{16}$ molecules

= $4x$ molecules

7 0

2 years ago

A 30. g sample of Aluminum was heated to 40. 0C and placed in a calorimeter containing 50. g of water at 21 0C. What is the fina

Darina [25.2K]

Answer: The final temperature will be $23^oC$

Explanation:

Calculating the heat released or absorbed for the process:

$q=m\times C\times (T_2-T_1)$

In a system, the total amount of heat released is equal to the total amount of heat absorbed.

$q_1=-q_2$

$m_1\times C_1\times (T_f-T_1)=-m_2\times C_2\times (T_f-T_2)$ ......(1)

where,

$C_1$ = specific heat of aluminium = $0.21 Cal/g^oC$

$C_2$ = heat capacity of water = $1Cal/g^oC$

$m_1$ = mass of aluminium = 30. g

$m_2$ = mass of water = 50. g

$T_f$ = final temperature of the system = ?

$T_1$ = initial temperature of aluminium = $40.^oC$

$T_2$ = initial temperature of the water = $21.^oC$

Putting values in equation 1, we get:

$30\times 0.21\times (T_f-40)=-50\times 1\times (T_f-21)\\\\56.3T_f=1302\\\\T_f=\frac{1302}{56.3}=23.13^oC=23^oC$

Hence, the final temperature will be $23^oC$

7 0

3 years ago

It takes 5.0 J of heat in increase the temp of a sample by 10 degrees Celcius. If the mass is doubled, how much heat in joules w

Alona [7]

Answer:

c. 10.0 J

Explanation:

The heat (Q) needed to increase the temperature of a certain mass of a sample can be calculated using the following expression:

Q = c . m . ΔT

where,

c is the heat capacity

m is the mass

ΔT is the change in temperature

Let's call Q₁ (5.0 J) the heat to increase the temperature of the mass m₁ by ΔT = 10.0°C.

Q₁ = c . m₁ . ΔT

If the mass is doubled (m₂ = 2 m₁), the heat required is:

Q₂ = c . m₂ . ΔT = c . 2 . m₁ . ΔT = 2 . c . m₁ . ΔT = 2 . Q₁

Q₂ = 2 . Q₁ = 2 . 5.0 J = 10.0 J

5 0

2 years ago

What is the principal quantum number value for the highest energy electron in carbon (atomic number 6)?

drek231 [11]

The principal quantum number for the highest energy electron in carbon would be 2. It is easy to spot this, since carbon exists in row 2 of the period table. The row in which an element resides always shows the highest value of n, or the principal quantum number, that an electron can reside in.

5 0

3 years ago