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a_sh-v [17]
3 years ago
11

Como se conserva la energia mecanica del cuerpo de un deportista

Physics
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

the energy  food has is transformed into mechanical energy during exercise,

Explanation:

When a person is exercising, the energy accumulated in food is transformed into mechanical energy, in general if he is running in kinetic energy and if he is rising and falling in potential energy.

In this case the energy  food has is transformed into mechanical energy during exercise,

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How much support force does a table exert on a book that weighs 15 N when the book is placed on the table?
mestny [16]

Answer:

15 N

Explanation:

According to Newton's third law of motion, to every action, there is an equal and opposite reaction. This reaction is equal in magnitude to the force acting but in an opposite direction.

Now, if the book weighs 15 N, an opposite equal force will be: N = -15 N

But the magnitude of this will be the absolute value which is 15N.

8 0
3 years ago
The amount of friction divided by the weight of an object forms a unit less number called the
Romashka [77]

Answer:

Coefficient of friction.

Explanation:

The amount of friction divided by the weight of an object is equal to the coefficient of friction. It is a dimensional less number. It can be given by :

F=\mu N

N is normal force.

\mu = coefficient of friction

\mu=\dfrac{F}{N}

3 0
3 years ago
A sample of an unknown substance has a mass of 0. 158 kg. If 2,510. 0 J of heat is required to heat the substance from 32. 0°C
guapka [62]

The specific heat of the unknown substance with a mass of 0.158kg is 0.5478 J/g°C

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

The specific heat capacity of a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

  • Q = quantity of heat absorbed (J)
  • c = specific heat capacity (4.18 J/g°C)
  • m = mass of substance
  • ∆T = change in temperature (°C)

According to this question, 2,510.0 J of heat is required to heat the 0.158kg substance from 32.0°C to 61.0°C. The specific heat capacity can be calculated:

2510 = 158 × c × (61°C - 32°C)

2510 = 4582c

c = 2510 ÷ 4582

c = 0.5478 J/g°C

Therefore, the specific heat capacity of the unknown substance that has a mass of 0.158 kg is 0.5478 J/g°C.

Learn more about specific heat capacity at: brainly.com/question/2530523

4 0
3 years ago
Adding heat to a liquid causes which of the following physical changes?
Nadya [2.5K]
Decreases density because gases have less density than liquids
4 0
3 years ago
Read 2 more answers
A soda has a volume of 560 mL and a density of 3.2 g/mL. What is the mass?
kolbaska11 [484]
The correct answer is: 1792g or 1800g.

(When you round it)
8 0
3 years ago
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