is it true that the composition of the atmosphere changes every few kilometers as you move away from earth

An object with an acceleration of –10 m/s² is _____.

Sidana [21]

The answer might be B because the value is negative, and negative could mean slowing down.

7 0

3 years ago

Jerome does not pay his balances off his credit cards each month. He often has to pay interest and finance charges. What is Jero

slega [8]

Jerome is referred to a debtor as he doesn't pay his balances off his credit cards each month.

<h3>Who is a Debtor?</h3>

This is defined as an individual who owes money while on the other hand a deadbeat is a person who pays his balances off his credit cards each month without having to pay interests.

Since jerome failed to pay the balances on the credit card then he is called a debtor.

Read more about Debtor here brainly.com/question/25919625

4 0

1 year ago

Which type of water body does water move the slowest?

Alex

In my text book for social studies it says a canal

7 0

3 years ago

Why is a flask is wider on the bottom than on the top? allows for a more precise measurement allows for better thermal equilibri

Genrish500 [490]

Answer:

allows for better thermal equilibrium

Explanation:

Due to the cone shape, most of the liquid will be closer to the bottom than the top. The large surface area of the bottom allows for faster heating.

8 0

2 years ago

A swimming pool is 50 ft wide and 100 ft long and its bottom is an inclined plane, the shallow end having a depth of 4 ft and th

Nina [5.8K]

Explanation:

We define force as the product of mass and acceleration.

F = ma

It means that the object has zero net force when it is in rest state or it when it has no acceleration. However in the case of liquids. just like the above mentioned case, the water is at rest but it is still exerting a pressure on the walls of the swimming pool. That pressure exerted by the liquids in their rest state is known as hydro static force.

Given Data:

Width of the pool = w = 50 ft

length of the pool = l= 100 ft

Depth of the shallow end = h(s) = 4 ft

Depth of the deep end = h(d) = 10 ft.

weight density = ρg = 62.5 lb/ft

Solution:

a) Force on a shallow end:

$F = \frac{pgwh}{2} (2x_{1}+h)$

$F = \frac{(62.5)(50)(4)}{2}(2(0)+4)$

$F = 25000 lb$

b) Force on deep end:

$F = \frac{pgwh}{2} (2x_{1}+h)$

$F = \frac{(62.5)(50)(10)}{2} (2(0)+10)$

$F = 187500 lb$

c) Force on one of the sides:

As it is mentioned in the question that the bottom of the swimming pool is an inclined plane so sum of the forces on the rectangular part and triangular part will give us the force on one of the sides of the pool.

1) Force on the Rectangular part:

$F = \frac{pg(l.h)}{2}(2(x_{1} )+ h)$