Answer:
Explanation:
tube:
f=v/4L = 343/(4*1.2)= 71.4583Hz tube's fundamental frequency
wire:
f=v/2L -> v=2Lf
v= 2*0.323*71.4583= 46.162m/s
ρ= 0.0095/0.323= 0.02941kg/m
v=√(T/ρ) -> T=v^2*ρ
T= 46.162^2*0.02941= 62.67[N] Tension of wire.
Answer:
Solution given;
load =600N
effort=?
load distance: 0.6m
effort distance;2.6m
we have
load *load distance :effort *effort distance
0.6*600=effort *2.6
360/2.6=effort
effort:138.46N
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Answer:
a. The object will attract the glass rod.
b. The object will repel the glass rod.
Explanation:
a. When you rub a plastic rod with wool, it becomes negatively charged. This is because the wool material loses some of its electrons to the plastic rod. The wool becomes positively charged while the plastic rod becomes negatively charged.
Hence, for an object to repel the negatively charged plastic rod, it must also be negatively charged. This is because objects with like charges repel one another.
On the other hand, when you rub a glass rod with a silk material, it becomes positively charged. This is because the glass rod loses its electrons to the silk material. The silk material then becomes negatively charged, while the glass rod becomes positively charged.
Therefore, the negatively charged object will attract the already positively charged glass rod.
b. For an object to attract a negatively charged plastic rod, then it must be positively charged, since unlike charges attract.
So, a positively charged object will repel the negatively charged glass rod.
Answer:
The pressure is 
Explanation:
From the question we are told that
The area of the edge is 
The force is 
The pressure is mathematically represented as

substituting values


Its the first one with the circle and the arrows going around it