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3 years ago

Which describes an image that can be produced by a concave lens?

Physics

2 answers:

harina [27]3 years ago

7 0

The image is virtual and smaller than the object is a description of an image that can be produced by a concave lens.

To add, concave lenses<span> are thinner at the middle. Rays of light that pass through the lens are spread out (they diverge). It is a type of diverging lens.</span>

Leviafan [203]3 years ago

6 0

The correct answer to this question is : 3) The image is virtual and smaller than the object .

EXPLANATION:

A concave lens is a diverging lens. It is an optically transparent spherically refracting surface which is bulged at the edges and thinner at the centre.

Due to its shape, the rays of light are diverged when allowed to pass through this lens. Hence, the image formed by this lens is virtual and erect.

The magnification of image produced by the lens is less than one i.e the size of image is smaller than size of object.

Hence, the image formed by the concave lens is virtual,erect and diminished.

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The lifetime of the particle is $\Delta t = 2.6*10^{-25} \ s$

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From the question we are told that

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A rifle bullet with mass ma = 8.00 g strikes and embeds itself in a block with mass mb = 0.992 kg that rests on a frictionless,

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the magnitude of the velocity of the block just after impact is 2.598 m/s and the original speed of the bullect is 324.76m/s.

Explanation:

a) Kinetic energy of block = potential energy in spring

½ mv² = ½ kx²

Here m stands for combined mass (block + bullet),

which is just 1 kg. Spring constant k is unknown, but you can find it from given data:

k = 0.75 N / 0.25 cm

= 3 N/cm, or 300 N/m.

From the energy equation above, solve for v,

v = v √(k/m)

= 0.15 √(300/1)

= 2.598 m/s.

b) Momentum before impact = momentum after impact.

Since m = 1 kg,

v = 2.598 m/s,

p = 2.598 kg m/s.

This is the same momentum carried by bullet as it strikes the block. Therefore, if u is bullet speed,

u = 2.598 kg m/s / 8 × 10⁻³ kg

= 324.76 m/s.

Hence, the magnitude of the velocity of the block just after impact is 2.598 m/s and the original speed of the bullect is 324.76m/s.

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3 years ago