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Serjik [45]
3 years ago
6

A. describe where to look on the periodic table to find Elements which have similar reactivity and other properties.

Chemistry
2 answers:
zloy xaker [14]3 years ago
7 0
A.
Elements in the same group have similar properties.

B.
The similarity in their properties arises from the fact that they have an equal number of valence shell electrons.

C.
Fluorine, Chlorine, Bromine
Lana71 [14]3 years ago
6 0

The periodic table is the arrangement of elements according to their atomic numbers [modern periodic law]

A) The elements which have similar properties are placed in same group.

The periodic table is arranged in 18 different groups based on the elements with similar properties

B) the elements of a group have similar properties due to similar outer electronic configuration or same valence electrons.

For example

C)

a) Alkali metals: they all have one electron in their outermost shell or they have one valence electron. due to this they can easily form cations by losing one electron and gain stable noble gas configuration.

Lithium, sodium and potassium

b) noble gases: they have completely filled outer shell or valence shell. So they are not much reactive and do not form compounds or molecules easily

Helium, neon, argon

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DIA [1.3K]

Answer:

(C) H3O+(aq) + C2H3O2−(aq) -> HC2H3O2(aq) + H2O(l)

Explanation:

A buffer is a solution of a weak acid and its salt. It mitigates against changes in acidity or alkalinity of a system. A buffer maintains the pH at a constant value by switching the equilibrium concentration of the conjugate acid or conjugate base respectively.

Addition if an acid shifts the equilibrium position towards the conjugate acid side while addition of a base shifts the equilibrium position towards the conjugate base side.

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3 years ago
This formula equation is unbalanced.
Afina-wow [57]
The balanced equation will read:

Pb(NO3)2 (aq) + LiSO4 (aq) ➡️ PbSO4 (s) + 2️⃣LiNO3 (aq)

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6 0
3 years ago
Read 2 more answers
Margret claimed that she needed 5.45 moles of Potassium Chloride, KCl to complete her experiment. How many grams of KCl does she
zubka84 [21]

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loiuygfcx

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3 0
3 years ago
3. A compound was analyzed and found to contain 9.8 g of nitrogen, 0.70 g of
Nesterboy [21]

Answer:

HNO₃

Explanation:

Data given

Nitrogen = 9.8 g

Hydrogen =  0.70 g

Oxygen = 33.6 g

Empirical formula = ?

Solution:

Convert the masses to moles

For Nitrogen

Molar mass of N = 14 g/mol

                              no. of mole = mass in g / molar mass

Put value in above formula

                          no. of mole = 9.8 g/ 14 g/mol

                          no. of mole = 0.7

                           mole of N = 0.7 mol

For Hydrogen

Molar mass of H = 1 g/mol

                     no. of mole = mass in g / molar mass

Put value in above formula

                     no. of mole = 0.70 g/ 1 g/mol

                      no. of mole = 0.7

mole of H = 0.7 mol

For Oxygen

Molar mass of O = 16 g/mol

                       no. of mole = mass in g / molar mass

Put value in above formula

                       no. of mole = 33.6 g / 16 g/mol

                       no. of mole = 2.1

mole of O = 2.1 mol

Now we have values in moles as below

N = 0.7

H = 0.7

O = 2.1

Divide the all values on the smallest values to get whole number ratio

N = 0.7 / 0.7 = 1

H = 0.7 / 0.7 = 1

O = 2.1 / 0.7 = 3

So all have following values

N = 1

H = 1

O = 3

So the empirical formula will be HNO₃ i.e. all three atoms in simplest small ratio.

6 0
3 years ago
A 255 ml gas sample contains argon and nitrogen gas at a temperature of 65 oc. the total pressure of the sample is 725 mmhg, and
Serhud [2]
We calculate first for the number of moles of gases in the sample through the ideal gas equation.
                                       n = PV/RT
      n = (725 mmHg/760 mmHg/atm)(0.255 L) / (0.0821 L.atm/mol.K)(65 + 273.15)  
                                       n = 8.76 x 10^-3 mol
Then, we calculate for the mol N2 using the ratio of the pressure.
                          n N2 = (8.76 x 10^-3 mols)(231 mmHg/725 mmHg)
                           n N2 = 2.79 x 10^-3 moles
Then, multiply the value with the molar mass of N2 which is 28 grams per mol giving us the answer of 0.078 grams. 
                                   
6 0
3 years ago
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