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skelet666 [1.2K]
1 year ago
13

So if you had corbphydrates and hydronic acids and you put them together what would be the radius?​

Chemistry
1 answer:
tankabanditka [31]1 year ago
4 0

Answer:

Based off of the 'so', this is not an actual question. This is a mix of math and chem.

But if you come up with a punchline... It's a joke!

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TRUE or FALSE
andriy [413]

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1. true

2. false

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19.
solmaris [256]

Answer:

В.  No, because the mass of the reactants is less than the mass of the products.

Explanation:

Chemical equation:

NaBr + Cl₂      →      2NaCl + Br₂

The given equation is not balanced because number of moles of sodium and bromine atoms are less on reactant side while more on the product side.

There are one mole of sodium and one mole of bromine atom on left side of equation while on right side there are 2 moles of bromine and 2 moles of sodium atom are present. The number of moles of chlorine atoms are balanced.

Balanced chemical equation:

2NaBr + Cl₂      →      2NaCl + Br₂

Now equation is balanced. Number of moles of sodium , chlorine and bromine atoms are equal on both side.

5 0
3 years ago
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7 0
2 years ago
The kb of hypochlorous acid is 3. 0×10^–8 at 26. 0 C. What is the percent of ionization of hypochlorous?
astraxan [27]

The acid dissociation constant (Ka) defines the difference between a weak and a strong acid. The % ionization of hypochlorous acid is 0.14%.

<h3>What is the acid dissociation constant?</h3>

The acid dissociation constant is used to define the ionization constant of an acidic substance. It gives the quantitative measurement of the strength.

The ICE table is attached to the image below.

The acid dissociation constant (Ka) for the reaction is,

Ka = [H⁺][ClO⁻] ÷ [HClO]

= a² ÷ (0.015 - a)

= 3.0 x 10⁻⁸

Now, a² + 3.0 x 10⁻⁸ a - 4.5 × 10⁻¹⁰ = 0

So, a = 2.210 × 10⁻⁵

Solving further,

[H+] = a = 2.210 × 10⁻⁵ M

The percent ionization is calculated as,

[H+] ÷ [HClO] × 100

= 2.210 × 10⁻⁵ M ÷ 0.015 × 100

= 0.14 %

Therefore, 0.14 % is the percentage of hypochlorous ionization.

Learn more about acid dissociation constant here:

brainly.com/question/22668939

#SPJ4

Your question is incomplete, but most probably your full question was, The ka of hypochlorous acid (HClO) is 3.0 x 10⁻⁸ at 25.0°C. What is the % of ionization of hypochlorous acid in a 0.015 aqueous solution of HClO at 25.0C?

6 0
1 year ago
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