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3 years ago

In physics, why would an equation like y=mx+b be plotted as a straight line rather than as a parabola, as is done in math?

Physics

1 answer:

notka56 [123]3 years ago

3 0

Answer:

Explanation:

In Both Physics and Math

y=mx+b is plotted as straight line where

m=slope of line

b=intercept on Y-axis

whereas Equation of parabola is something like this

$y^2=4ax$

$x^2=4ay$

Math is a tool to solve Physics problems so equations are same in math and physics

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Degrees of loudness and softness in music are called.

andrey2020 [161]

Degrees of loudness and softness in music are called dynamics. I don’t really have an explanation for this, that’s just what they’re called. I know because I’m a violinist and learned it when I first started playing.

7 0

3 years ago

#4 HELP PLEASE! Find Gravitational Potential Energy! THANK YOU!

Scilla [17]

Answer:

$\Delta GPE=-3.92\ 10^9\ J$

Explanation:

Gravitational Potential Energy

It's the capacity of an object to do work due to its relative height from a fixed reference point.

It's computed as

GPE=m.g.h

Where m is the mass of the object, h is its height and g is the acceleration of gravity, $g=9.8 m/sec^2$

The mass of water is given as

$m=8,000,000\ kg$

The height above the rocks is h=50 m. Let's compute the GPE

$GPE_1=(8,000,000\ kg)(9.8\ m/s^2)(50\ m)$

$GPE_1=3,920,000,000\ Joule$

It should be expressed in scientific notation

$GPE_1=3.92\ 10^9\ J$

The GPE at the bottom, where h=0

$GPE_2=0$

The change of gravitational potential energy is:

$\Delta GPE=GPE_2-GPE_1$

$\boxed{\Delta GPE=-3.92\ 10^9\ J}$

8 0

3 years ago

A proton travels at a velocity of 3.0x10^6 m/s in a direction perpendicular to a uniform magnetic field.

Virty [35]

Answer:

0.239 T

Explanation:

Applying,

F = Bvqsin∅................ Equation 1

Where F = magnetic force, B = magnetic Field, q = charge of a proton, v = velocity of proton, ∅ = angle between the velocity and the magnetic field.

make B the subject of the equation

B = F/(vqsin∅)................. Equation 2

From the question,

Given: F = 1.15×10⁻¹³ N, v = 3.0×10⁶ m/s, ∅ = 90°(perpendicular)

Constant: q = 1.602 x 10⁻¹⁹ C

Substitute into equation 2

B = 1.15×10⁻¹³ /(3.0×10⁶×1.602 x 10⁻¹⁹×sin90°)

B = 1.15×10⁻¹³/(4.806×10⁻¹³)

B = 0.239 T.

Hence the magnetic field = 0.239 T

7 0

3 years ago

In the carbon cycle, carbon is transferred from animals to decomposers in all of the following ways EXCEPT

Ad libitum [116K]

Hello.

The answer is C) as carbon dioxide.

Have a nice day

7 0

3 years ago

Read 2 more answers

You have a remote-controlled car that has been programmed to have velocity v⃗ =(−3ti^+2t2j^)m/s, where t is in s. At t = 0 s, th

DiKsa [7]

Answer:

The y-component of the car's position vector is 670m/s.

The x-component of the acceleration vector is -3, and the y-component is 40.

Explanation:

The displacement vector of the car with velocity

$\boldsymbol{v}= (-3t\boldsymbol{i}+2t^2\boldsymbol{j})m/s$

is the integral of the velocity.

Integrating $\boldsymbol{v}$ we get the displacement vector $\boldsymbol{d}$ :

$\boldsymbol{d}=(-\dfrac{3}{2}t^2\boldsymbol{i}+\dfrac{2}{3}t^3\boldsymbol{j} )$

Now if the initial position if the car is

$\boldsymbol{r}= (3.0\boldsymbol{i}+2.0\boldsymbol{j})$

then the displacement of the car at time $t$ is

$\boldsymbol{d(t)}= \boldsymbol{r+d}$

$\boxed{\boldsymbol{d(t)}=(-\dfrac{3}{2}t^2+3.0\boldsymbol{i}+\dfrac{2}{3}t^3+2.0\boldsymbol{j} )}$

Now at $t=10s$ , we have

$\boxed{\boldsymbol{d(t)}=(-147\boldsymbol{i}+670\boldsymbol{j} )}m$

The y-component of the car's position vector is 670m/s.

The acceleration vector is the derivative of the velocity vector:

$\boldsymbol{a(t)}=\dfrac{d\boldsymbol{v(t)}}{dt} =(-3\boldsymbol{i}+4t\boldsymbol{j})$

and at $t=10s$ it is

$\boldsymbol{a(t)}=(-3\boldsymbol{i}+40\boldsymbol{j})m/s^2$

The x-component of the acceleration vector is -3, and the y-component is 40.

5 0

3 years ago