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Gwar [14]
3 years ago
6

a 8000kg tow truck pulls a 3000kg car horizontally into a garage. if the motor of the tow truck exerts a forward thrust on the t

ruck of 800N, what is the tension in the cable connecting the truck to the car? (neglect any forces of friction)
Physics
1 answer:
Evgen [1.6K]3 years ago
8 0
Equation 1 :
m1 :   m1a =T 
Equation 2:m2 : m2a= F - T 

Adding 1 and 2a=0.073

Placing in  equation 1

we get T = 218.18N
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Explanation:

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for the initial spinning condition, we take moment of inertial = I'

for final spinning condition, we take moment of inertia = I

initial angular momentum = ω'I' = 130 I'

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according to conservation of angular momentum, initial angular momentum must be equal to the final angular momentum, therefore

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ratio of initial moment of inertia to final moment of inertia = I'/I

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2.63 = 375/ω'

ω' = 375/2.63 = <em>143.13 rpm</em>

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