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Gwar [14]
3 years ago
6

a 8000kg tow truck pulls a 3000kg car horizontally into a garage. if the motor of the tow truck exerts a forward thrust on the t

ruck of 800N, what is the tension in the cable connecting the truck to the car? (neglect any forces of friction)
Physics
1 answer:
Evgen [1.6K]3 years ago
8 0
Equation 1 :
m1 :   m1a =T 
Equation 2:m2 : m2a= F - T 

Adding 1 and 2a=0.073

Placing in  equation 1

we get T = 218.18N
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timofeeve [1]

Explanation:

A double replacement reaction is a reaction in which two different compounds are mixed together and both their cations and anions get exchanged with each other respectively.

When potassium bromide reacts with silver nitrate then it results in the formation of potassium nitrate and silver bromide.

The chemical reaction equation is as follows.

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6 0
3 years ago
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A golfer hits her tee-shot due north towards the fairway. Her shot has an initial velocity of 60 m/s. A 15 m/s wind is blowing i
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Answer:

c=71.4m/s

\theta=8.54\textdegree

Explanation:

From the question we are told that

Initial velocity of 60 m/s

Wind speed V_w= 15 m/s \angle  45 \textdegree

Generally Resolving vector mathematically

  sin(45\textdegree)15=10.6\\cos(45\textdegree)15=10.6

Generally the equation Pythagoras theorem is given mathematically by

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c=\sqrt{10.6^2 +(10.6+60)^2}

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c=71.4m/s

b)Resultant direction

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\theta=tan^-1(\frac{y}{x})

Therefore

\theta=tan^-1(\frac{10.6}{70.6})

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2 years ago
Determine the approximate force (N) used to pull a sled up a 400 m hill using 1900 J of work.
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The work done to pull the sled up to the hill is given by
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where
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d is the distance where the force is applied.

In our problem, the work done is W=1900 J and the distance through which the force is applied is d=400 m, so we can calculate the average force by re-arranging the previous equation and by using these data:
F= \frac{W}{d}= \frac{1900 J}{400 m} = 4.75 N \sim 5 N
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