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Gwar [14]
3 years ago
6

a 8000kg tow truck pulls a 3000kg car horizontally into a garage. if the motor of the tow truck exerts a forward thrust on the t

ruck of 800N, what is the tension in the cable connecting the truck to the car? (neglect any forces of friction)
Physics
1 answer:
Evgen [1.6K]3 years ago
8 0
Equation 1 :
m1 :   m1a =T 
Equation 2:m2 : m2a= F - T 

Adding 1 and 2a=0.073

Placing in  equation 1

we get T = 218.18N
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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

vo = 25 m/sec 
<span>vf = 0 m/sec </span>
<span>Fμ = 7100 N (Force due to friction) </span>
<span>Fg = 14700 N </span>
<span>With the force due to gravity, you can find the mass of the car: </span>
<span>F = ma </span>
<span>14700 N = m (9.8 m/sec²) </span>
<span>m = 1500 kg </span>
<span>Now, we can use the equation again to find the deacceleration due to friction: </span>
<span>F = ma </span>
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<span>vf² = vo² + 2a∆d </span>
<span>0 = (25 m/sec)² + 2 (-4.73333333333 m/sec²) ∆d </span>
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<span>-625 m²/sec² = (-9.466666666667 m/sec²) ∆d </span>
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