Question

Water is boiled in a pan on a stove at sea level. During 10 min of boiling, it is observed that 200 g of water has evaporated. Then the rate of heat transfer to the water is 225.7 kJ/min 45.1 kJ/min 53.5 kJ/min 0.84 kJ/min 41.8 kJ/min

Answer 1

Answer:

Rate of heat is 45.1 kJ/min

Explanation:

Heat required to evaporate the water is given by

Q = mL

here we know that

$L = 2.25 \times 10^6 J/kg$

now we have

$Q = (0.200)(2.25 \times 10^6 J/kg)$

$Q = 452.1 kJ$

now the power is defined as rate of energy

$P = \frac{Q}{t}$

$P = \frac{452.1 kJ}{10}$

$P = 45.1 kJ/min$