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3 years ago

Alberto y David roban un coche y huyen a 90 km/h. A los 10 minutos, la policía recibe

Physics

1 answer:

Alborosie3 years ago

8 0

Answer:

Explanation:

Given that,

Albert and David steal a car and run at

Vt = 90km/hr

Vt = 90×1000/3600 = 25m/s

After 10minutes

t = 10×60 = 600seconds

The police are inform and they started chasing at

Vp = 120km/hr

Vp = 120 × 1000/3600 = 33.33m/s

A. The thief have been running for 1200seconds before the police start

So, the distance between the thief and the police at the start can be determine using

Speed = distance / time taken

So, distance = speed × time taken

d = Vt × t

d = 25 × 600

d = 15,000m

d = 15 km

So, the thief are 15km apart from the thief after 10 minutes

B. Let assume we want to know when police will catch up with the thief.

Now,

The thief is traveling at 25m/s

And police = 33.33m/s

The distance apart is 15,000m

So, let assume the police will catch the thief at distance 'do, then the thief had already travelled 15,000, so the thief will have d - 15000. Note that they will spend the same time in this reference.

So, let find the time the police will traveled 'd'

Speed = distance / time

distance = speed of police × time

d = Vp × t

d = 33.33t...........equation 1

Also, the thief

Distance = speed of thief × time

15,000-d = 25 × t.........equation 2

Substitute equation 1 into 2

15,000 - 33.33t = 25t

15,000 = 25t + 33.33t

15,000 = 58.33t

t = 257.14 seconds

So, it will take the police a total of 600second before they were told and the time 257.14 second when they caught the thief.

How long will it have been after the robbery?

Total time after robbery before the car was recovered is

t = 600 + 257.14

t = 857.14 seconds

In Spanish

Dado que,

Albert y David roban un auto y corren a

Vt = 90 km / h

Vt = 90 × 1000/3600 = 25 m / s

Después de 10 minutos

t = 10 × 60 = 600 segundos

La policía está informada y comenzaron a perseguir a

Vp = 120 km / h

Vp = 120 × 1000/3600 = 33.33 m / s

A. El ladrón ha estado corriendo durante 1200 segundos antes de que comience la policía.

Entonces, la distancia entre el ladrón y la policía al inicio se puede determinar usando

Velocidad = distancia / tiempo necesario

Entonces, distancia = velocidad × tiempo tomado

d = Vt × t

d = 25 × 600

d = 15,000m

d = 15 km

Entonces, el ladrón está a 15 km del ladrón después de 10 minutos

B. Supongamos que queremos saber cuándo la policía alcanzará al ladrón.

Ahora,

El ladrón viaja a 25 m / s.

Y policía = 33.33m / s

La distancia es de 15,000m.

Entonces, supongamos que la policía atrapará al ladrón a distancia 'do, entonces el ladrón ya había viajado 15,000, por lo que el ladrón tendrá d - 15000. Tenga en cuenta que pasarán el mismo tiempo en esta referencia.

Entonces, busquemos el tiempo en que la policía viajará 'd'

Velocidad = distancia / tiempo

distancia = velocidad de la policía × tiempo

d = Vp × t

d = 33.33t ........... ecuación 1

Además, el ladrón

Distancia = velocidad del ladrón × tiempo

15,000-d = 25 × t ......... ecuación 2

Sustituye la ecuación 1 en 2

15,000 - 33.33t = 25t

15,000 = 25t + 33.33t

15,000 = 58.33t

t = 257.14 segundos

Entonces, le tomará a la policía un total de 600 segundos antes de que se les diga y el tiempo 257.14 segundos cuando atraparon al ladrón.

¿Cuánto tiempo habrá pasado después del robo?

El tiempo total después del robo antes de recuperar el automóvil es

t = 600 + 257,14

t = 857.14 s

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