What is the definition of diploid

if the same amount of heat is added to 50.0 g samples of each of the metals, which are all at the same temperature, which metal

Salsk061 [2.6K]

The metal which will reach the highest temperature is the metal with the lowest specific heat capacity.

<h3>What is the amount of heat added to each metal?</h3>

The amount of heat Q = mcΔT where

m = mass of metal
c = specific heat capacity of mateal and
ΔT = temperature change

<h3>Temperature change of the metal</h3>

Making ΔT subject of the formula, we have

ΔT = Q/mc

Given that Q and m are the same for each metal,

ΔT ∝ 1/c

We see that the temperature change is inversely proportional to the specific heat capacity.

Since the metals are at the same temperature, the metal which will reach the highest temperature is the metal with the lowest specific heat capacity.

So, the metal which will reach the highest temperature is the metal with the lowest specific heat capacity.

Learn more about temperature here:

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6 0

1 year ago

HELP PLEASE ASAP

Anna [14]

Answer:

d

Explanation:

Aluminium and Indian are in the same group/family

Sodium and Sulfer are in the same period

Elements of the same family have similar properties

Since sulfur and sodium aren't in the same family they dont share properties

3 0

2 years ago

Two samples of carbon come into contact. A heat transfer will occur between sample A and sample B. What must be true for heat to

jarptica [38.1K]

Answer:

The average kinetic energy of A is greater than that of B.

Explanation:

The temperature of an object is directly proportional to the average kinetic energy of the particles in the object. For instance, for an ideal gas, we have

$KE=\frac{3}{2}kT$

where

KE is the kinetic energy

k is the Boltzmann constant

T the absolute temperature of the gas

Therefore, this means that in a hotter object the average kinetic energy of the particles is higher than the average kinetic energy of the particles in a colder object.

Moreover, the laws of thermodynamics tell us that heat is always transferred from a hotter object (higher temperature) to a colder object (lower temperature).

In this problem heat is transferred from sample A to sample B. Therefore, this means that object A has higher temperature, and therefore, higher average kinetic energy. So the correct answer is

The average kinetic energy of A is greater than that of B.

8 0

2 years ago

Read 2 more answers

Unknown element has two isotopes. Isotope A has a mass of 34 amu and abundance of 52%, isotope B has a mass of 33 amu and abunda

ZanzabumX [31]

Answer:

x = 33.52 amu

Explanation:

It is given that,

Isotope A has a mass of 34 amu and an abundance of 52%, isotope B has a mass of 33 amu and an abundance of 48%.

Let x is the average atomic mass of this element. It can be calculated as follows :

$x=52\%\ \text{of}\ 34+48\%\ \text{of}\ 33\\\\x=\dfrac{52}{100}\times 34+\dfrac{48}{100}\times 33\\\\x=0.52\times 34+0.48\times 33\\\\x=33.52\ \text{amu}$

So, the average atomic mass of this element is 33.52 amu.

4 0

3 years ago

How many grams of nan3 are required to produce 19.0 ft3 of nitrogen gas, about the size of an automotive air bag, if the gas has

Papessa [141]

The balanced chemical reaction is given as:

$2NaN_{3}(s)\rightarrow 2Na(s)+3N_{2}(g)$

Now, convert $19.0 ft^{3}$ into litres.

$1 ft^{3} = 28.3168$

So, $19.0 ft^{3} = 19\times 28.3168 = 538.0192 L$

Density is equal to the ratio of mass to the volume.

$D=\frac{M}{V}$

where, M = mass and V= volume $(538.0192 L)$

Substitute the value of density and volume in formula to get the value of mass.

$1.25 g/L=\frac{M}{538.0192 L}$

$1.25 g/L\times 538.0192 L= M$

$Mass = 672.524 g$

Now, number of moles of $N_{2}$ gas= $\frac{672.524 g}{28.02 g/mol}$

= $24.00 moles$

According to the reaction, 2 moles of sodium azide gives 3 moles of nitrogen gas.

Now, in 24.00 moles of nitrogen gas produced from= $\frac{2 moles of sodium azide}{3 moles of nitrogen gas}\times 24.00 moles$ of nitrogen gas, moles of sodium azide.

number of moles of sodium azide = $16 moles$

Mass of sodium azide in g = $number of moles\times molar mass of sodium azide$ .

= $16 moles\times 65.00 g/mol$

= $1040 g$

Thus, mass of sodium azide which is required to produce $19.0 ft^{3}$ of nitrogen gas = $1040 g$

3 0

2 years ago