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3 years ago

Name and describe the three quantized particles

Physics

1 answer:

padilas [110]3 years ago

4 0

Answer:

The three quantized particles are:

1. Electrons

2. Protons

3. Neutrons

Explanation:

Quantization can be defined as the conversion of a continuous quantity into discrete set of values.

It can also be defined as the concept which says that the particles exist as the smallest finite and discrete value known as quanta which not be divided further.

The three particles include:

1. The electron bound inside an atom have quantized momentum and energy.

2. The proton bound in the inside of a nucleus has energy in the quantized form only.

3. Also the nucleus bound neutron is also a quantized particle.

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Read 2 more answers

*A car is going through a dip in the road whose curvature approximates a circle of radius 150m. At what velocity will the occupa

Valentin [98]

Answer:

v= 14.85 m/s

Explanation:

When at the bottom of the dip, the only force that keeps the car in the circular trajectory, is the centripetal force.
This force is not a new force, is just the net force aiming to the center of the circle.
In this case, is just the difference between the normal force (always perpendicular to the surface, pointing upward) and the force that gravity exerts on the car (which is known as the weight), pointing downward.
So, we can write the following expression:

$F_{cent} = F_{n} - F_{g} (1)$

It can be showed that the centripetal force is related to the speed by the following expression:
$F_{cent} = m*\frac{v^{2}}{r} (2)$

The normal force, it is called the apparent weight, because it would be the weight as measured by a scale.
Replacing (2) in (1), and solving for Fn, we get:

$F_{n} = m*\frac{v^{2} }{r} + m*g (3)$

Now, we need to find the value of v that makes Fn, exactly 15% more than the weight m*g, so we can write the following equation:

$F_{n} = 1.15*F_{g} = m*\frac{v^{2}}{r} +F_{g} (4)$

Replacing Fg by its value, simplifying, and solving for v, we get:

$v = \sqrt{0.15*g*r} = \sqrt{9.8 m/s2*0.15*150m} = 14.85 m/s (5)$

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3 years ago