The pendulum has a kinetic energy of 330 J at the bottom of its swing.
when a pendulum oscillates, the energy at its highest point is wholly potential, since it is momentarily at rest at the highest point. The pendulum experiences acceleration which is directed towards the mean position, as a result of which its speed increases. It has maximum speed at the point which is at the bottom of its swing.
As the pendulum swings from the highest to the lowest point, the potential energy at the highest point is converted into kinetic energy.
If air resistance can be neglected, one can apply the law of conservation of energy, which states that the total energy of a system remains constant.
In this case, the potential energy of 330 J at the highest point would be equal to the kinetic energy at the bottom point.
Therefore, the kinetic energy at the bottom of its swing will be 330 J.
Weight of object = mass x acceleration due to gravity
= 2.5 x 9.8
= 24.5N
Hence option B is correct.
Hope this helps!!
Answer:
This is an example of Inelastic colission
Explanation:
Step one:
given:
mass of moose m1 = 620 kg
mass of train m2= 10,000kg
Initial velocity of moose u1= 0 m/s
Initial velocity of train v1 = 10m/s
combined velocity of the system is given as v
Applying the conservation of momentum equation we have
m1u1+ m2u1= (m1+m2)V
substitutting we have
620*0+10000*10= (620+10000)V
100000= 10620V
divide both sides by 10620
V = 100000/10620
V=9.41m/s
The velocity of the moose after impact is 9.41m/s
Answer:
Explanation:
Given:
dI/dt = 6.21 A/s
n = N/l
= 100 turns/cm
= 100 turns/cm × 100 cm/1 m
Radius, r = 14.7 cm
= 0.147 m
Inductance, L = uo × n^2 × A × l
L/l = 4pi × 10^-7 × (100 × 100)^2 × pi × 0.147^2
= 8.53 H
Emf, E = L × dI/dt
E/l = L/l × dI/dt
= 8.53 × 6.21
= 52.98 V/m
=
