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disa [49]
3 years ago
13

How much power is used by a car engine if it does 48496 J of work in 4 min?

Physics
2 answers:
elena-14-01-66 [18.8K]3 years ago
8 0

<em>Hope this will help u</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>✌</em><em>✌</em><em>✌</em>

cupoosta [38]3 years ago
6 0

Answer:

hope it helps uh.............

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If velocity is in m/s and time is in sec, what is the unit of acceleration?​
WINSTONCH [101]
The unit of acceleration would be m/s² :)
6 0
2 years ago
Why are “input” and “output” good words to use when discussing systems?
charle [14.2K]

Answer:

To determine how efficient that system is.

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3 years ago
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How far from Earth must a space probe be along a line toward the Sun so that the Sun's gravitational pull on the probe balances
Tatiana [17]

Answer:

258774.9441 m

Explanation:

x = Distance of probe from Earth

y = Distance of probe from Sun

Distance between Earth and Sun = x+y=149.6\times 10^6\ m

G = Gravitational constant

M_s = Mass of Sun = 1.989\times 10^{30}

M_e = Mass of Earth = 5.972\times 10^{24}\ kg

According to the question

\frac{GM_sm}{x^2}=\frac{GM_em}{y^2}\\\Rightarrow \frac{M_s}{x^2}=\frac{M_e}{y^2}\\\Rightarrow x=\sqrt{\frac{M_s\times y^2}{M_e}}\\\Rightarrow x=\sqrt{\frac{1.989\times 10^{30}\times y^2}{5.972\times 10^{24}}}\\\Rightarrow x=577.10852y

x+y=149.6\times 10^6\\\Rightarrow 577.10852y+y=149.6\times 10^6\\\Rightarrow 578.10852y=149.6\times 10^6\\\Rightarrow y=\frac{149.6\times 10^6}{578.10852}\\\Rightarrow y=258774.9441\ m

The probe should be 258774.9441 m from Earth

7 0
3 years ago
A book sitting on a shelf has gravitational potential energy. true or false
Darya [45]

Answer:

False

Explanation:

A book resting on a shelf has no potential energy relative to the shelf, since it has height of zero meters relative to the shelf.

8 0
3 years ago
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A 57-gram tennis ball moving at 70 miles per hour is hit with a 110-gram tennis racquet moving at 60 miles per hour. Which state
Whitepunk [10]

Answer:

D. Because mass and energy are both conserved, the total amounts of mass and energy are the same before and after impact.

Explanation:

As we know that, the energy in motion is Kinetic Energy mathematically given as:

KE=\frac{1}{2} m.v^2

<u>Now, according to the law of conservation of energy:</u>

\frac{1}{2} m_1.u_1^2+\frac{1}{2} m_2.u_2^2=\frac{1}{2} m_1.v_1^2+\frac{1}{2} m_2.v_2^2

where:

m_1\ \&\ m_2 mass of racquet and ball respectively and u_1\ \&\ u_2 are their respective initial velocities.

v_1\ \&\ v_2 are the respective final velocities.

<u>Also the law of conservation of momentum is applicable in this case:</u>

m_1.u_1+ m_2.u_2= m_1.v_1+m_2.v_2

In this case the velocity of the lighter mass will get increases in the final condition.

5 0
3 years ago
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