Answer:
32.8g/mole
Explanation:
Given parameters:
Mass of sample of gas = 32.8g
Volume = 22.4L
Unknown:
Molecular weight = ?
Solution:
To solve this problem we must understand that at rtp;
1 mole of gas occupies a volume of 22.4L
Number of mole of the gas = 1 mole
Now;
Mass = number of moles x molecular weight
molecular weight =
=
= 32.8g/mole
Answer:
I believe the answer is C
Answer:
rocky surface covered with landforms
Explanation:
<u>Answer:</u> For the given reaction, the value of
is greater than 1
<u>Explanation:</u>
For the given chemical equation:

The expression of
for above equation follows:
![K_c=\frac{[Ca^{2+}]\times [CO_3^{2-}]}{[CaCO_3}]\\\\K_c=[Ca^{2+}]\times [CO_3^{2-}]](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCa%5E%7B2%2B%7D%5D%5Ctimes%20%5BCO_3%5E%7B2-%7D%5D%7D%7B%5BCaCO_3%7D%5D%5C%5C%5C%5CK_c%3D%5BCa%5E%7B2%2B%7D%5D%5Ctimes%20%5BCO_3%5E%7B2-%7D%5D)
The concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression
As, the denominator is missing and the numerator is the only part left in the expression. So, the value of
will be greater than 1.
Hence, for the given reaction, the value of
is greater than 1