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Radda [10]
3 years ago
15

Help not to sure with this one need help plz asap​

Physics
2 answers:
katen-ka-za [31]3 years ago
8 0
25,200 meters is the answer
DiKsa [7]3 years ago
4 0

A is the answer for the problem

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An object possessing an excess of 6.0x10^6 electrons has a net charge of
guajiro [1.7K]
A single electron has a charge of
e=-1.6 \cdot 10^{19}C
Therefore, if we have an excess of N=6.0\cdot10^6 electrons, the total net charge will be the product between the charge of a single electron and the total number of electrons in excess:
Q=Ne=(6.0\cdot10^6)(-1.6 \cdot 10^{-19}C)=9.6 \cdot 10^{-13}C
7 0
4 years ago
What direct current in A will produce the same amount of thermal energy, in a particular resistor, as an alternating current tha
vodomira [7]

Answer:

I_{rms}= 4.314 AExplanation:According to the definition of the root mean square value of current, the value of direct current which passes through the same circuit in which an alternating current is passing and producing same amount of heat as the direct current produced is called root mean square value of current. So, the relation between the root mean square value of current and the peak value of alternating current is given by [tex]I_{rms}=\frac{I_{0}}{\sqrt{2}}

I_{rms}=\frac{6.1}}{\sqrt{2}}

[tex]I_{rms}= 4.314 A

6 0
3 years ago
This is a net gain or loss of electrons. *
krok68 [10]
A net gain of electrons.
8 0
3 years ago
Read 2 more answers
If you wish to take a picture of a bullet traveling at 500 m/s, then a very brief flash of light produced by an RC discharge thr
Agata [3.3K]

Answer:

Resistance in the flash tube, R=3.97\times 10^{-3}\ \Omega

Explanation:

It is given that,

Speed of the bullet, v = 500 m/s

Distance between one RC constant, d = 1 mm = 0.001 m

Capacitance, C=503\ \mu F=503\times 10^{-6}\ F

The time constant of RC circuit is given by :

\tau=RC

R is the resistance in the flash tube

R=\dfrac{\tau}{C}..........(1)

Speed of the bullet is given by total distance divided by total time taken as :

v=\dfrac{d}{\tau}

\tau=\dfrac{d}{v}

\tau=\dfrac{0.001}{500}

\tau=0.000002\ s

Equation (1) becomes :

R=\dfrac{0.000002}{503\times 10^{-6}}

R=3.97\times 10^{-3}\ \Omega

So, the resistance in the flash tube is 3.97\times 10^{-3}\ \Omega. Hence, this is the required solution.

8 0
3 years ago
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How can we get a clue as to the temperature of a star
Juli2301 [7.4K]
The colour of the star and the brightness. 
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3 years ago
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