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Naya [18.7K]
3 years ago
14

Jim ran 200 meters in 30.4 seconds. Mac ran 100 meters in 30.4 seconds. Who ran faster?

Chemistry
2 answers:
VladimirAG [237]3 years ago
7 0

Jim, because he ran a greater distance in the same time :)

By the way, this is a maths question

aleksandrvk [35]3 years ago
4 0
Jim ran faster hope that helped you out my boy
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Does density depend on the amount of substance that you have? Explain your answer.
Natasha_Volkova [10]

Answer:

Density depends on the amount of the substance you have, as the mass will increase, but also what the volume is because if you have a high mass object with an extremely high volume, it won't be very dense. But if you have a high mass object with a low volume, it will be very dense.

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8 0
3 years ago
Calculate the ratio of effusion rates of cl2 to f2 .
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6 0
3 years ago
The names and chemical formulae of some chemical compounds are written in the first two columns of the table below. Each compoun
charle [14.2K]

Answer:

See below  

Explanation:

<u>          Name         </u>  <u>Formula </u>      <u>       Major species     </u> <u>  </u>        

Zinc iodide              ZnI₂            H₂O(ℓ),  I⁻(aq), Zn²⁺(aq),  

Nitrogen(I) oxide     N₂O           H₂O(ℓ),  N₂O(aq)

Sodium nitrite         NaNO₂      H₂O(ℓ),  Na⁺(aq), NO₂⁻(aq)

Glucose                   C₆H₁₂O₆    H₂O(ℓ),  C₆H₁₂O₆(aq)

Nickel(II) iodide       NiI₂            H₂O(ℓ),  I⁻(aq), Ni²⁺(aq)

  • Glucose and nitrogen(I) oxide are covalent compounds. They do not dissociate in solution.
  • The compounds containing metals are ionic. They produce ions in solution.
  • ZnI₂ and NiI₂ produce twice as many iodide ions as metal ions.
6 0
3 years ago
The volume of a sample gas, initially at 25 C and 158 mL, increased to 450 mL. What is the final temperature of the sample of ga
Rashid [163]

Answer:

Final temperature of the gas is  576 ^{0}\textrm{C}.

Explanation:

As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:

                                       \frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

where V_{1} and V_{2} are volume of gas at T_{1} and T_{2} temperature (in kelvin scale) respectively.

Here V_{1}=158mL , T_{1}=(273+25)K=298K and V_{2}=450mL

So  T_{2}=\frac{V_{2}T_{1}}{V_{1}}=\frac{(450mL)\times (298K)}{(158mL)}=849K 

849 K = (849-273) ^{0}\textrm{C} = 576 ^{0}\textrm{C}

So final temperature of the gas is  576 ^{0}\textrm{C}.

3 0
3 years ago
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