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3 years ago

What ion is Calcium most likely to form? and how do you know?

Chemistry

1 answer:

vlada-n [284]3 years ago

7 0

Answer: Ca2+

Explanation: calcium is most like to form Ca2+ because it has 2 electrons in it outermost shell. So it can only contribute 2 electrons for bonding.

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What is the equilibrium constant expression for the ksp of sr3(po4)2?

Eddi Din [679]

The equilibrium constant expression for KSP of Sr3(PO4)2 is

KSP={(Sr^2+)^3 (PO4^3-)^2/ Sr3(PO4)2}

Explanation

write the ionic equation for Sr3(PO4)2

Sr3(PO4)2 → 3Sr^2+ + 2 PO4^3-

KSP is given by (concentration of the products raised to their coefficient /concentration of reactants raised to their coefficient)

7 0

3 years ago

Read 2 more answers

Cocaine selectively blocks na+ (sodium) channels, which is the mechanism that leads to

anzhelika [568]

Cocaine selectively blocks sodium channels which is the mechanism that leads to local anesthetic effects.
Voltage gated sodium channels play very important roles in the body as they are responsible for action initiation and propagation in excitable cells, such as nerves, muscles and neuroendocrine cells. Like other sodium ion channels blockers such as lidocaine, Cocaine selectively blocks sodium ion channels which denies entry of sodium ions in the cell, thus leading to local anesthetic effects.

5 0

3 years ago

Find the molarity of 131 g Ba(NO3)2 dissolved in 750.0 water

storchak [24]

Answer:

6.68 x 10^-4

Explanation:

131g ÷ 261.337g/mol = 0.5012685 moles

0.5012685 moles ÷ 750.0 liters =

0.5012685÷ 750.0=0.000668358

6.68 x 10^-4

8 0

2 years ago

A specific steroid has a λmax of 257 nm and a molar absorptivity ε of 11 , 500 L mol − 1 cm − 1 . What is the concentration of t

joja [24]

Answer:

$7.83\times 10^{-6} M$ is the concentration of the compound in a solution.

Explanation:

Using Beer-Lambert's law :

Formula used :

$A=\epsilon \times C\times l$

Where:

A = absorbance of solution

C = concentration of solution

l = path length

$\epsilon$ = molar absorptivity coefficient

We have:

C = ? , l = 1.00 cm, A = 0.090

$\epsilon = 11,500 L/(mol cm)$

$C=\frac{A}{\epsilon l}=\frac{0.090}{11,500 L/(mol cm)\times 1.00 cm}$

$C=7.83\times 10^{-6} M$

$7.83\times 10^{-6} M$ is the concentration of the compound in a solution.

6 0

3 years ago

Sighting along the C2-C3 bond of 2-methylbutane, the least stable conformation (Newman projection) has a total energy strain of

natima [27]

Answer:

21 KJ/mol

Explanation:

For this question, we have to start with the linear structure of 2-methylbutane. With the linear structure, we can start to propose all the Newman projections keep it in mind that the point of view is between carbons 2 and 3 (see figure 1).

Additionally, we have several energy values for each interaction present in the Newman structures:

-) Methyl-methyl gauche: 3.8 KJ/mol

-) Methyl-H eclipse: 6.0 KJ/mol

-) Methyl-methyl eclipse: 11.0 KJ/mol

-) H-H eclipse: 4.0 KJ/mol

Now, we can calculate the energy for each molecule.

Molecule A

In this molecule, we have 2 Methyl-methyl gauche interactions only, so:

(3.8x2) = 7.6 KJ/mol

Molecule B

In this molecule, we have a Methyl-methyl eclipse interaction a Methyl-H eclipse interaction and an H-H eclipse interaction, so:

(11)+(6)+(4) = 21 KJ/mol

Molecule C

In this molecule, we have 1 Methyl-methyl gauche interaction only, so:

3.8 KJ/mol

Molecule D

In this molecule, we have three Methyl-H eclipse interaction, so:

(6*3) = 18 KJ/mol

Molecule E

In this molecule, we have 1 Methyl-methyl gauche interaction only, so:

3.8 KJ/mol

Molecule F

In this molecule, we have a Methyl-methyl eclipse interaction a Methyl-H eclipse interaction and an H-H eclipse interaction, so:

(11)+(6)+(4) = 21 KJ/mol

The structures with higher energies would be less stable. In this case, structures B and F with an energy value of 21 KJ/mol (see figure 2).

I hope it helps!

3 0

3 years ago