Answer:
370.6 nm
Explanation:
wavelength in vacuum = 494 nm
refractive index of water with respect to air = 1.333
Let the wavelength of light in water is λ.
The frequency of the light remains same but the speed and the wavelength is changed as the light passes from one medium to another.
By using the definition of refractive index
where, n be the refractive index of water with respect to air
By substituting the values, we get
λ = 370.6 nm
Thus, the wavelength of light in water is 370.6 nm.
Answer:
V = (Vx^2 + Vy^2)^1/2 = (40^2 + 62^2)^1/2
V = 73.8 m/s
tan theta = Vy / Vx = 62/40 = 1.55
theta = 57.2 deg
Answer:
5.71 m/s ;
20 m/s
Explanation:
Blue car:
At time, t = 0 ; Initial position = 20 m
Final position, = 60m after 4 seconds
The velocity = change in distance / change in time.
Velocity of blue = (60 - 20)m ÷ ((4 + 3) - 0),
Velocity of blue car = 40 / 7
= 5.71 m/s
Red car:
Initial Position = 0 ; final Position = 60
Time taken = 3 seconds
Velocity of Red car = (60 - 0)m ÷ 3
Velocity of Red car = 60 / 3
= 20 m/s
Answer:
a= 17.69 m/s^2
Explanation:
Step one:
given data
A car accelerates uniformly from rest to 23 m/s
u= 0m/s
v= 23m/s
distance= 30m
Step two:
We know that
acceleration= velocity/time
also,
velocity= distance/time
23= 30/t
t= 30/23
t= 1.30 seconds
hence
acceleration= 23/1.30
accelaration= 17.69 m/s^2
Answer:
velocity = 16.67[m/s]
Explanation:
To solve this problem we must use the following expression of speed, where we see the relationship between displacement and time.
velocity = displacement/time [m/s]
displacement = 50 [m]
time = 3 [s]
velocity = 50/3
velocity = 16.67[m/s]
