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Wewaii [24]
3 years ago
12

The function g(x) is defined as shown.

Mathematics
2 answers:
Evgen [1.6K]3 years ago
4 0
G(x) = 6 - x for x = 3 and above.
Therefore, g(3) = 6 - 3 = 3
lubasha [3.4K]3 years ago
4 0

Answer:

3


Step-by-step explanation:

This is a piece-wise function. The domain [x-values] is broken down into parts.

<em>To evaluate this type of functions, we see in </em><em>WHICH PART</em><em> of the </em><em>DOMAIN</em><em> does the questions ask to look for.</em>

The question asks for g(3) , the value of the function at  x=3

<em>In which of the 3 parts does  x=3  fall into?</em>


The domain condition,  x\geq3  , in the last part tells us that it is GREATER THAN OR EQUAL TO 3. So  x=3  falls in this part of the function, which is  6-x

We can simply substitute 3 in x of that part and get our desired answer. So,

6-x\\6-(3)\\3

The value of g(3)=3

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Answer:

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Step-by-step explanation: because if you break them apart you will get 2 or 4

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3 years ago
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In the arithmetic sequence {13,6,−1,−8,…}, what is the common difference?
Charra [1.4K]

Answer:

-7

Step-by-step explanation:

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3 years ago
Equivalent to 10 minus 8
Reptile [31]
1+1


Hope this helps!
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4 years ago
10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the
Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

H_0: \mu = 0

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

H_1: \mu > 0

<h3>What is the test statistic?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

In this problem, the parameters are given as follows:

\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50.

Hence, the test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by t^{\ast} = 2.4.

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

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2 years ago
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agasfer [191]

Answer:

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Step-by-step explanation:

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