Give a possible molecular formula for the empirical formula of c3h5clo.
1 answer:
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Answer:
ΔP = -3556.36 Pa
Explanation:
Atmospheric pressure, P = 101300 Pa
Latent heat of boiling water,
Boiling point at atmospheric pressure, T = 373.15 K
ΔT = 1 K
The change in volume as the water boils to vapor will be
Since the volume of vapor () is far greater than the volume of liquid (
)
Using the ideal gas equation:
R = 8.314 J/mol-K
ΔV = 0.0306 m³
Molecular weight of water, MW = 0.018 kg/mol
Using the Clausius - Clapeyron equation:
ΔP = -3556.36 Pa
But the pressure change is said to lower the boiling point of water, only a negative pressure change will lower the boiling point.
ΔP = 3556.36 Pa
The allowable combination for the atomic orbital is n=4, l=2, =2.
Three quantum numbers specify an atomic orbital:
- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.
- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),
- is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus;
values are integers from -l to =l(l limits ml)
For n = 4, l can four values: 0, 1, 2, and 3. To be consistent with =+2the l value must be higher than 1. There are two l values that are consistent with n and
values: l= 2 or 3
Therefore, the allowable condition is n=4, l=2, =2
To know more about quantum numbers, visit: brainly.com/question/16979660
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