Answer:
About 108 times
Step-by-step explanation:
Given:
An average soccer player travels 7 miles during a game
A typical field is 104 meters long.
To find:
How many times did the average soccer play travel the length of the field?
Solution:
An average soccer player travels during the game = 7 miles
First convert 7 miles into meters, 1 mile = 1609.34 meter
7 mile = 1609.34 \times 7 = 11265.41 m
Length of field = 104 meters
To find number of times average soccer player travel the length of the field, we will divide an average soccer player travels during the game by Length of field
11265.41 m
104 = 108.32
Therefore, about 108 times average soccer player travel the length of the field
Answer:
-4 degrees Farenheit
Step-by-step explanation:
8-12=-4
Answer:
One solution
Step-by-step explanation:
5x + y = 8
15x + 15y = 14
Lets solve using substitution, first we need to turn "5x + = 8" into "y = mx + b" or slope - intercept form
So we solve for "y" in the equation "5x + y = 8"
5x + y = 8
Step 1: Subtract 5x from both sides.
5x + y − 5x = 8 − 5x
Step 2: 5x subtracted by 5x cancel out and "8 - 5x" are flipped
y = −5x + 8
Now we can solve using substitution:
We substitute "-5x + 8" into the equation "15x + 15y = 14" for y
So it would look like this:
15x + 15(-5x + 8) = 14
Now we just solve for x
15x + (15)(−5x) + (15)(8) = 14(Distribute)
15x − 75x + 120 = 14
(15x − 75x) + (120) = 14(Combine Like Terms)
−60x + 120 = 14
Step 2: Subtract 120 from both sides.
−60x + 120 − 120 = 14 − 120
−60x = −106
Divide both sides by -60

Simplify

Now that we know the value of x, we can solve for y in any of the equations, but let's use the equation "y = −5x + 8"





















So there is only one solution to the equation.
Okay so just do this equation below.
92,000 x 0.06
And you have your answer!
Answer is 5,520.
Leave a 5 star rating, a thanks, and a most brainy answer!
Answer:
x=12, y= 20
Step-by-step explanation:
We can find x using the pythagorean thereom because ABD is a right triangle.(D is the point between segments with legnth 5 and 11)
AC^2 + CD^2 = AD^2
x^2 + 5^2 = 13^2
x^2 = 25 = 169
x^2 = 144
x = 12
We may now find y using the pythagorean thereom because ABC is a right triangle. Right now we know x = 12
AC^2 + CB ^2 = AB^2
12^2 + 16^2 = y^2
144 + 256 = y^2
y^2 = 400
y= 20
<em>I hope this helps! :)</em>