If there is a large enough amount of water vapor in the air and the tempature is hot enough cloud or storms can form.
Archimedes principle states
that
F1 / A1 = F2 / A2
F2 = (A2 / A1) * F1
Also, formula for the force is
F = mg. Formula for the area of the cylinder is A = πr^2, therefore we get
F2 = (πr2^2 / πr1^2) * mg
Since the diameter of the
cylinders are 2 cm and 24 cm, r1 = 12 and r2 = 1.
Substituting the values to the
derived equation, we get
F2 = (π 1^2 / π 12^2) * 2400 * 9.8
F2 = 163.3333 N
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The period of the transverse wave from what we have here is 0.5
<h3>How to find the period of the transverse wave</h3>
The period of a wave can be defined as the time that it would take for the wave to complete one complete vibrational cycle.
The formula with which to get the period is
w = 4π
where w = 4 x 22/7
2π/T = 4π
6.2857/T = 12.57
From here we would have to cross multiply
6.2857 = 12.57T
divide through by 12.57
6.2857/12.57 = T
0.500 = T
Hence we can conclude that the value of T that can determine the period based on the question is 0.500.
Read more on transverse wave here
brainly.com/question/2516098
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Answer:
The box will be moving at 0.45m/s. The solution to this problem requires the knowledge and application of newtons second law of motion and the knowledge of linear motion. The vertical component of the force Fp acts vertically upwards against the directio of motion. This causes a constant upward force of 23sin45° to act on the box. Fhe frictional force of 13N also acts vertically upwards and so two forces act upwards against rhe force of gravity resulting un a net force of 0.7N acting kn the box. This corresponds to an acceleration of 0.225m/s². So in w.0s after i start to push v = 0.45m/s.
Explanation:
Answer with Explanation:
We are given that
Weight of an ore sample=17.5 N
Tension in the cord=11.2 N
We have to find the total volume and the density of the sample.
We know that
Tension, T=
=buoyancy force
T=Tension force
W=Weight
By using the formula

N

Where
=Volume of object
=Density of water
=Acceleration due to gravity
Substitute the values then we get


Volume of sample=
Density of sample,
Where mass of ore sample=1.79 kg
Substitute the values then, we get

Density of the sample=