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netineya [11]
2 years ago
7

What are the importance of crystallography in geology

Engineering
1 answer:
olganol [36]2 years ago
8 0

Answer:Crystallography is useful in phase identification. When performing any process on a material, it may be desired to find out what compounds and what phases are present in the material. Each phase has a characteristic arrangement of atoms.

Explanation:

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A steam power plant with a power output of 230 MW consumes coal at a rate of 60 tons/h. If the heating value of the coal is 30,0
NARA [144]

Answer:

\eta =46\%

Explanation:

Hello!

In this case, we compute the heat output from coal, given its heating value and the mass flow:

Q_H=60\frac{tons}{h}*\frac{1000kg}{1ton}*\frac{1h}{3600s}*\frac{30,000kJ}{kg}\\\\Q_H=500,000\frac{kJ}{s}*\frac{1MJ}{1000J} =500MW

Next, since the work done by the power plant is 230 MW, we compute the efficiency as shown below:

\eta =\frac{230MW}{500MW}*100\% \\\\\eta =46\%

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7 0
3 years ago
Design a PLC ladder logic program to control the operation of a conveyor-storage system using the following sequence: - 1. Progr
Phantasy [73]

Answer:

See explaination

Explanation:

Kindly check attachment for the step by step solution of the given problem.

8 0
3 years ago
Air pressure is higher above an airfoil.<br> true or false
attashe74 [19]

Answer: true

Explanation:

it flows faster over the top of the wing because the top is more curved than the bottom of the wing. However

6 0
3 years ago
A cylindrical specimen of some metal alloy having an elastic modulus of 124 GPa and an original cross-sectional diameter of 4.2
IrinaVladis [17]

Answer:

the maximum length of the specimen before deformation is 0.4366 m

Explanation:

Given the data in the question;

Elastic modulus E = 124 GPa = 124 × 10⁹ Nm⁻²

cross-sectional diameter D = 4.2 mm = 4.2 × 10⁻³ m

tensile load F = 1810 N

maximum allowable elongation Δl = 0.46 mm = 0.46 × 10⁻³ m

Now to calculate the maximum length l for the deformation, we use the following relation;

l = [ Δl × E × π × D² ] / 4F

so we substitute our values into the formula

l = [ (0.46 × 10⁻³) × (124 × 10⁹) × π × (4.2 × 10⁻³)² ] / ( 4 × 1810 )

l = 3161.025289 / 7240

l = 0.4366 m

Therefore, the maximum length of the specimen before deformation is 0.4366 m

5 0
3 years ago
Select the correct answer.
Lilit [14]

Answer:

D

Explanation:

Confidential data is not supposed to be shared amongst others.

8 0
3 years ago
Read 2 more answers
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