Given:
Circumference = 2 m
Angular speed, ω = 1 rev/s = 2π radians/s
If the radius is r, then
2πr = 2
r = 1/π m
The linear (tangential) speed is
v = rω
= (1/π m)*(2π rad/s) = 0.5 m/s
Answer: 0.5 m/s
The thing that pushes the object up while it is falling is air. This force is known as "air resistance".
Answer:
a)- 1.799 rad/sec²
b)- 17.6 x 10ˉ³Nm
Explanation:
ω₀ = 720 rev/min x (1 min/60 sec) x (2π rad / 1 rev) = 24π rad/s
a) Assuming a constant angular acceleration, the formula will be
α = (ωf -ω₀) / t
As final state of the grindstone is at rest, so ωf =0
⇒ α = (0-24π) / 41.9 = - 1.799 rad/sec²
b)Moment of inertia I for a disk about its central axis
I = ½mr²
where m=2kg and radius 'r'= 0.099m
I = ½(2)(0.099²)
I = 9.8 x 10ˉ³ kgm²
Next is to determine the frictional torque exerted on the grindstone, that caused it to stop, applying the rotational equivalent of the Newton's 2nd law:
τ = I α =>(9.8 x 10ˉ³)(- 1.799)
τ = - 17.6 x 10ˉ³Nm
(The negative sign indicates that the frictional torque opposes to the rotation of the grindstone).
Acceleration is given by:

where
v is the final velocity
u is the initial velocity
t is the time interval
Let's apply the formula to the different parts of the problem:
A) 
Let's convert the quantities into SI units first:


t = 4.0 min = 240 s
So the acceleration is

B) 
As before, let's convert the quantities into SI units first:


t = 94 s
So the acceleration is

C) 
For this part we have to use a different formula:

where we have
v = 0 is the final velocity
u = 89.2 m/s is the initial velocity
a is the acceleration
d = 75 m is the distance covered
Solving for a, we find

C. Bottom
Titania speaks these words as she is under the enchantment of the magic flower, it makes her fall in love with the first thing she sees. It's comedic because Bottom is also enchanted to have the head of a donkey, so she's claiming that this peasant with a donkey head is both wise and beautiful. The reality being that he is as wise as he is beautiful, in that he is neither beautiful nor wise.