Answer:- Oxidation number of Cl does not change as it is -1 on both sides.
Explanations:- oxidation number of Mg on reactant side is 0 as it is in its elemental form(not combined with another element).
Oxidation number of hydrogen in its compounds is +1, so if H is +1 in HCl the oxidation number of Cl is -1 as the sum has to be zero.
On product side, Mg oxidation number is +2 as the oxidation number of alkaline earth metals in their compounds is +2.
Two Cl are present in magnesium chloride, so if Mg is +2 then Cl is -1.
Oxidation number of H on product side is 0 as it is present in its elemental for, 
,
So, it is only chlorine(Cl) whose oxidation number does not change for the given equation.
The gastric chief cells of the stomach secrete enzymes for protein breakdown (inactive pepsinogen, and in infancy rennin). Hydrochloric acid activates pepsinogen into the enzyme pepsin, which then helps digestion by breaking the bonds linking amino acids, a process known as proteolysis.
Answer:
25mL
Explanation:
Please see the step-by-step solution in the picture attached below.
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Answer;
K+ and NO3- ions
Explanation;
The main ions remaining are K+ and NO3- ions after pbi2 precipitation is complete.
However; There will always be tiny amounts of Pb2+ and I- ions, but most of them are in the solid precipitate.
Answer:
Ionic bond is formed by the opposite ions attraction between the 2 atoms in an ionically bonded compound. The two ions i.e. Cation and Anions are formed by oxidation and reduction reactions respectively. General Ionic formula is as follow,
Mⁿ⁺ + Nⁿ⁻ → MN
where;
Mⁿ⁺ = Cation
Nⁿ⁻ = Anion
MN = Salt
Explanation:
Ionic bond is the electrostatic forces of attraction between positively charged cations and negatively charged Anions. These forces are very stronger resulting in increasing several physical properties of Ionic compounds like melting point and boiling point e.t.c.
Example:
Sodium Chloride:
NaCl is formed by Na⁺ cation and Cl⁻ anion as follow,
Oxidation of Na;
2 Na → 2 Na⁺ + 2 e⁻
Reduction of Cl₂;
Cl₂ + 2 e⁻ → 2 Cl⁻
Crystal Lattice formation is as follow,
Na⁺ + Cl⁻ → NaCl
