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3 years ago

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Which chemical equation is a model of a decomposition reaction?

1 answer:

blagie [28]3 years ago

3 0

A is a model of a decomposition reaction

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N76 [4]

Answer + Explanation:

1. The different ways tectonic plates move in relation to each other are:

convergent (where plates move into one another)

divergent (where plates move apart)

transform (where plates move sideways in relation to each other)

2. Convergent plate boundaries can result in:

earthquakes, volcanoes, and the formation of mountains.

The Himalaya Mountains are the result of convergent plate boundaries.

3. Landforms that are a result of divergent boundaries are rift valleys and mid-oceanic ridges.

Locations where this occurs are: Mid-Atlantic Ridge, Red Sea Rift, Baikal Rift Zone

, East African Rift, East Pacific Rise, Gakkel Ridge, Galapagos Rise, and Explorer Ridge.

4. Transforming plate boundaries results in shallow earthquakes, large lateral displacement of rock, and a broad zone of crustal deformation.

A location where this occurs is: San Andreas Fault in western California

<em>sorry that's all I can help you with today :/ if I have more time I'll answer the other questions!! If I helped you please don't forget to mark me brainliest!!</em>

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8 0

3 years ago

Starting with 2.50 mol of N2 gas (assumed to be ideal) in a cylinder at 1.00 atm and 20.0C, a chemist first heats the gas at con

arsen [322]

Answer:

a) $T_b=590.775k$

b) $W_t=1.08*10^4J$

d) $Q=3.778*10^4J$

d) $\triangle V=4.058*10^4J$

Explanation:

From the question we are told that:

Moles of N2 $n=2.50$

Atmospheric pressure $P=100atm$

Temperature $t=20 \textdegree C$

$t = 20+273$

$t = 293k$

Initial heat $Q=1.36 * 10^4 J$

a)

Generally the equation for change in temperature is mathematically given by

$\triangle T=\frac{Q}{N*C_v}$

Where

$C_v=Heat\ Capacity \approx 20.76 J/mol/K$

$T_b-T_a=\frac{1.36 * 10^4 J}{2.5*20.76 }$

$T_b-293k=297.775$

$T_b=590.775k$

b)

Generally the equation for ideal gas is mathematically given by

$PV=nRT$

For v double

$T_c=2*590.775k$

$T_c=1181.55k$

Therefore

$PV=Wbc$

$Wbc=(2.20)(8.314)(1181_590.778)$

$Wbc=10805.7J$

Total Work-done $W_t$

$W_t=Wab+Wbc$

$W_t=0+1.08*10^4$

$W_t=1.08*10^4J$

c)

Generally the equation for amount of heat added is mathematically given by

$Q=nC_p\triangle T$

$Q=2.20*2907*(1181.55-590.775)\\$

$Q=3.778*10^4J$

d)

Generally the equation for change in internal energy of the gas is mathematically given by

$\triangle V=nC_v \triangle T$

$\triangle V=2.20*20.76*(1181.55-293)k$

$\triangle V=4.058*10^4J$

3 0

3 years ago