Answer:
23.60 mL NaOH
Explanation:
The reaction is CH3COOH + OH- --> CH3COO+ + H2O
Since the reaction is one-to-one, we can use M1V1 = M2V2.
M1 = 0.1894 M CH3COOH
V1 = 25.00 mL CH3COOH
M2 = 0.2006 M NaOH
V2 = ?
Solve for V2 --> V2 = M1V1/M2
V2 = (0.1894 M)(25.00 mL) / (0.2006 M) = 23.60 mL NaOH
Answer:
ΔG°rxn = -69.0 kJ
Explanation:
Let's consider the following thermochemical equation.
N₂O(g) + NO₂(g) → 3 NO(g) ΔG°rxn = -23.0 kJ
Since ΔG°rxn < 0, this reaction is exergonic, that is, 23.0 kJ of energy are released. The Gibbs free energy is an extensive property, meaning that it depends on the amount of matter. Then, if we multiply the amount of matter by 3 (by multiplying the stoichiometric coefficients by 3), the ΔG°rxn will also be tripled.
3 N₂O(g) + 3 NO₂(g) → 9 NO(g) ΔG°rxn = -69.0 kJ
