It dives at a constant rate of 2.4166666666666667 feet per second which would be 145 feet per minute and 8,700 feet per hour
Answer:

Step-by-step explanation:
We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.
We know that equation of an object's height t seconds after the launch is in form
, where
g = Force of gravity,
= Initial velocity,
= Initial height.
For our given scenario
,
and
. Upon substituting these values in object's height function, we will get:

Therefore, the function for the height of the arrow would be
.
Answer: 1) c 2) a 3) d
<u>Step-by-step explanation:</u>

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Reference angle is the angle measurement from the x-axis. <em>There is no such thing as a negative reference angle.</em>
-183° is 3° from the x-axis so the reference angle is 
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Coterminal means the same angle location after one or more<em> </em>rotations either clockwise or counter-clockwise.
To find these angles, add <em>or subtract</em> 360° from the given angle to find one rotation, add <em>or subtract</em> 2(360°) from the given angle to find two rotations, etc.
To find ALL of the coterminals, add <em>or subtract</em> 360° as many times as the number of rotations. Rotations can only be integers. In other words, you can only have ± 1, 2, 3, ... rotations. You cannot have a fraction of a rotation.
Given: 203°
Coterminal angles: 203° ± k360°, k ∈ <em>I</em>
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