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Delvig [45]
3 years ago
12

Write a balanced half-reaction for the reduction of permanganate ion (Mno) to manganese ion Mn?) in acidic aqueous solution. Be

sure to add physical state symbols where appropriate. 0-0 Cb X 5 2
Chemistry
1 answer:
Luden [163]3 years ago
6 0

Explanation:

Permanganate is general name for the chemical compound which containes manganate (VII) ion. Permanganate(VII) ion is strong oxidizing agent as  manganese is in +7 oxidation state and can be easily reduced and oxidize others.

The balanced half reaction for reduction of the permanganate ion, MnO_4^- to manganese ion, Mn^{2+} is shown below:

MnO_4^-_{(aq)}+8H^+_{(aq)}+5e^-\rightarrow Mn^{2+}_{(aq)}+4H_2O_{(l)}

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How much energy is required to heat 40g of water from -7 degrees Celsius to 108 degrees Celsius (Lf= 335,000J/Kg for ice)
solniwko [45]
The   energy  required  to heat  40g  of water  from -7 c  to 108 c is
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     calculation

Q(heat)=  M( mass)  x c(specific heat capacity) xdelta t( change in temperature)

M=  40g=  40/1000= 0.04 Kg
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3 years ago
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two critical requirements must be met before light elements, like hydrogen or helium, will fuse and form heavier elements. The t
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4 0
3 years ago
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A quantity of water is heated from 25.0°C to 36.4°C by absorbing 325 J of heat energy. If the specific heat of water is 4.18 J /
Arlecino [84]

Answer:

6,8 g

Explanation:

c = 4.18 J/(g * °C) = 4180 J / (kg * °C)

t_{1} = 25 °C

t_{2} = 36,4 °C

Q = 325 J

The formula is: Q = c * m * (t_{2} - t_{1})

m = \frac{Q}{c * (t_{2} - t_{1} )}

Calculating:

m = 325 / 4180 * (36,4 - 25) ≈ 0,0068 kg = 6,8 g

6 0
3 years ago
Does a metal conduct electricity in the solid state?
ad-work [718]
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In a shorter term - no
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3 years ago
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