Answer:
3.0 g daily dose
Explanation:
First of all, the given dose is measured in milligrams per kilogram of body and the mass of this patient is given in pounds. This means we have to begin this problem by converting the units.
Convert the mass into kilograms:
![224~lbs\cdot \frac{1~kg}{2.205~lb} = 101.6~kg](https://tex.z-dn.net/?f=224~lbs%5Ccdot%20%5Cfrac%7B1~kg%7D%7B2.205~lb%7D%20%3D%20101.6~kg)
Knowing that the dose is 15.0 mg per kilogram of body, one dose is equal to:
![101.6~kg\cdot \frac{15.0~mg}{1~kg} = 1524~mg](https://tex.z-dn.net/?f=101.6~kg%5Ccdot%20%5Cfrac%7B15.0~mg%7D%7B1~kg%7D%20%3D%201524~mg)
This is a single dose. If we wish to calculate the daily dose, since it's used twice, we get:
![1524~mg/dose\cdot 2~doses/day = 3048~mg = 3.0~g](https://tex.z-dn.net/?f=1524~mg%2Fdose%5Ccdot%202~doses%2Fday%20%3D%203048~mg%20%3D%203.0~g)
Answer:
2.58g
Explanation:
First calculate the moles of butane used in the reaction
moles = mass÷molar mass
= 0.85÷58
= 0.0147
According to the stoichiometric ratio:
C4H10 : CO2 = 2:8
moles of CO2 =(8÷2)×0.0147
=0.0586 moles
mass of CO2 = 0.0586×44
= 2.58g
The molecules are more loose and not as compact and bonded together by hydrogen bonds as solids. Liquid water also has an indefinite shape meaning it can shift into anything