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valentinak56 [21]
2 years ago
11

A sample of gas is placed into an enclosed cylinder and fitted with a movable piston. Calculate the work (in joules) done by the

gas if it expands from 5.33 L to 11.05 L against a pressure of 1.50 atm.
Chemistry
1 answer:
Nuetrik [128]2 years ago
6 0

Explanation:

here is the answer. Feel free to ask for more chem help

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How many grams of Cl2 are in 1.20 x 1024 Cl atoms?
Vaselesa [24]
<h3>Answer:</h3>

70.906 g

<h3>Explanation:</h3>

We are given;

  • Atoms of Chlorine = 1.2 × 10^24 atoms

We are required to calculate the mass of Chlorine

  • We know that 1 mole of an element contains atoms equivalent to the Avogadro's number, 6.022 × 10^23.
  • That is , 1 mole of an element = 6.022 × 10^23 atoms
  • Therefore; 1 mole of Chlorine = 6.022 × 10^23 atoms

But since Chlorine gas is a molecule;

  • 1 mole of Chlorine gas = 2 × 6.022 × 10^23 atoms

But, molar mass of Chlorine gas = 70.906 g/mol

Then;

70.906 g Of chlorine gas = 2 × 6.022 × 10^23 atoms

                                          = 1.20 × 10^24 atoms

Thus;

For 1.2 × 10^24 atoms ;

= ( 70.906 g/mol × 1.2 × 10^24 atoms ) ÷ (1.20 × 10^24 atoms)

<h3>=  70.906 g </h3>

Therefore, 1.20 × 10^24 atoms of chlorine contains a mass of 70.906 g

=  

5 0
3 years ago
the latest weather report includes the following statement: the temperature is 78°f, barometric pressure is 29 and the relative
NeX [460]

Answer:

78

Explanation:

6 0
3 years ago
How many moles are in 5.5 x 10-23 molecules of H2O
masha68 [24]

Answer:

0.914moles

Explanation:

The number of moles in a substance can be got by dividing the number of atoms/molecules/particles by Avagadro's constant (6.02 × 10^23).

That is;

number of moles (n) = number of atom (nA) ÷ 6.02 × 10^23

According to this question, there are 5.5 x 10-23 molecules of H2O

n = 5.5 x 10^23 ÷ 6.02 × 10^23

n = 0.914 × 10^(23-23)

n = 0.914 × 10^0

n = 0.914 × 1

n = 0.914moles

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3 years ago
What particle has almost mo mass
coldgirl [10]
Photon has no mass at all
6 0
3 years ago
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What is the current produced when a 12-Volt battery encounters a resistance of 20 Ohms?
Verdich [7]

Answer:

Explanation:

V = IR

I = V/R

I = (12V)/(20Ω)

I = 0.6 A

4 0
3 years ago
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