A sample of gas is placed into an enclosed cylinder and fitted with a movable piston. Calculate the work (in joules) done by the
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Molarity is defined as the ratio of number of moles to the volume of solution in litres.
The mathematical expression is given as:
Here, molarity is equal to 1.43 M and volume is equal to 785 mL.
Convert mL into L
As, 1 mL = 0.001 L
Thus, volume = = 0.785 L
Rearrange the formula of molarity in terms of number of moles:
n =
= 1.12255 mole
Now, Number of moles =
Molar mass of potassium hydroxide = 56.10 g/mol
1.12255 mole =
mass in g =
= 62.97 g
Hence, mass of = 62.97 g
The maximum height at which nitrogen molecule will go before coming to rest is 14 kilometers.
Given:
The nitrogen gas molecule with a temperature of 330 Kelvins is released from Earth's surface to travel upward.
To find:
The maximum height of a nitrogen molecule when released from the Earth's surface before coming to rest.
Solution:
- The maximum height attained by nitrogen gas molecule = h
- The temperature of nitrogen gas particle = T = 330 K
The average kinetic energy of the gas particles is given by:
The nitrogen molecule at its maximum height will have zero kinetic energy as all the kinetic energy will get converted into potential energy
- The potential energy at height h =
- Molar mass of nitrogen gas = 28.0134 g/mol
- Mass of nitrogen gas molecule = m
- The acceleration due to gravity = g = 9.8 m/s^2
- The maximum height attained by nitrogen gas molecule = h
- The potential energy is given by:
The maximum height at which nitrogen molecule will go before coming to rest is 14 kilometers.
Learn more about the average kinetic energy of gas particles here:
If you place 1.0 L of ethanol (C2H5OH) in a small laboratory that is 3.0 m long, 2.0 m wide, and 2.0 m high, will all the alcohol evaporate? If some liquid remains, how much will there be? The vapor pressure of ethyl alcohol at 25 °C is 59 mm Hg, and the density of the liquid at this temperature is 0.785g/cm^3 .
will all the alcohol evaporate? or none at all?
Answer:
Yes, all the ethanol present in the laboratory will evaporate since the mole of ethanol present in vapor is greater. The volume of ethanol left will therefore be zero.
Explanation:
Given that:
The volume of alcohol which is placed in a small laboratory = 1.0 L
Vapor pressure of ethyl alcohol at 25 ° C = 59 mmHg
Converting 59 mmHg to atm ; since 1 atm = 760 mmHg;
Then, we have:
=
= 0.078 atm
Temperature = 25 ° C
= ( 25 + 273 K)
= 298 K.
Density of the ethanol = 0.785 g/cm³
The volume of laboratory = l × b × h
= 3.0 m × 2.0 m × 2.5 m
= 15 m³
Converting the volume of laboratory to liter;
since 1 m³ = 100 L; Then, we have:
15 × 1000 = 15,000 L
Using ideal gas equation to determine the moles of ethanol in vapor phase; we have:
PV = nRT
Making n the subject of the formula; we have:
n = 47. 88 mol of ethanol
Moles of ethanol in 1.0 L bottle can be calculated as follows:
Since numbers of moles =
and mass = density × vollume
Then; we can say ;
number of moles =
number of moles =
number of moles =
number of moles = 17.039 mol
Thus , all the ethanol present in the laboratory will evaporate since the mole of ethanol present in vapor is greater. The volume of ethanol left will therefore be zero.