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2 years ago

What causes a satellite to move tangentially to a circular path?

Physics

2 answers:

yawa3891 [41]2 years ago

5 0

Explanation : We know that two forces acting on the satellite.

The speed of the satellite and the force of the gravity on the satellite then the result , the satellite moves around the earth in a circular motion.

A satellite to move tangentially to a circular path, while revolving around the circular path because the centripetal force is acting on it.

So, we can say gravity is responsible for the motion of the satellite in a circular path.

mezya [45]2 years ago

3 0

Answer: tangential velocity

The tangential velocity is the velocity the body presents at a given moment of time when describing a circular movement, taking into account its direction, as well as the radius by which it is traveling in a particular fraction of its trajectory.

To calculate tangential velocity, it is possible to take the angular velocity as a reference, nevertheless it is necessary to understand that it can be constant, while the tangential velocity can vary at each step, given the alterations of the path.

This is possible because movement of a satellite around the planet Earth is a good example of uniform circular motion, which is characterized by the movement of a body describing a circumference of a given radius with constant speed.

Therefore in this movement the velocity has a constant magnitude, but its direction varies continuously.

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A cruise ship makes its way from one island to another. The ship is in motion compared with which reference point?

jekas [21]

A reference point would be something not on the ship which could be used to calculate distance traveled.

Answer: C.) A lighthouse on a nearby Island

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2 years ago

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A force of 5.00 N to the left causes a 1.35 kg book to have a net acceleration of 0.76 m/s2 to the left. What is the frictional

Nuetrik [128]

Answer:

4.0 N

Explanation:

Sum the forces in the x direction:

∑F = ma

F − Fr = ma

Fr = F − ma

Fr = 5.00 N − (1.35 kg) (0.76 m/s²)

Fr = 4.0 N

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2 years ago

A flutist assembles her flute in a room where the speed of sound is 342m/s . When she plays the note A, it is in perfect tune wi

USPshnik [31]

Answer:

a.3Hz

b.0.0034m

Explanation:

First, we know the flute is an open pipe, because open pipe as both end open and a close organ pipe as only one end close.

The formula relating the length and he frequency is giving as

$f=\frac{nv}{2l}\\$ .

a.we first determine the length of the flute at the fundamental frequency i.e when n=1 and when the speed is in the 342m/s

Hence from

$f=\frac{nv}{2l}\\\\l=\frac{342}{2*440}\\ l=0.389m\\$ .

since the value of the length will remain constant, we now use the value to determine the frequency when the air becomes hotter and the speed becomes 345m/s.

$f=\frac{nv}{2l} \\f=\frac{345}{2*0.389}\\f=443.4Hz$

Hence the require beat is

$B=/f_{1}-f_{2}/\\B=/440-443/\\B=3Hz$ .

b. since the length is dependent also on the speed and frequency, we determine the new length when she plays with a fundamental frequency when the speed of sound is 345m/s

using the formula

$L_{new}=\frac{v}{2f}\\\\L_{new}=\frac{345}{2*440}\\\\L_{new}=0.39204$