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iragen [17]
3 years ago
10

What causes a satellite to move tangentially to a circular path?

Physics
2 answers:
yawa3891 [41]3 years ago
5 0

Explanation : We know that two forces acting on the satellite.

The speed of the satellite and the force of the gravity on the satellite then the result , the satellite moves around the earth in a circular motion.

A satellite to move tangentially to a circular path, while revolving around the circular path because the centripetal force is acting on it.

So, we can say gravity is responsible for the motion of the satellite in a circular path.

mezya [45]3 years ago
3 0

Answer: tangential velocity


The tangential velocity is the velocity the body presents at a given moment of time when describing a circular movement, taking into account its direction, as well as the radius by which it is traveling in a particular fraction of its trajectory.

To calculate tangential velocity, it is possible to take the <u>angular velocity</u> as a reference, nevertheless it is necessary to understand that it can be <u>constant</u>, while the tangential velocity can vary at each step, given the alterations of the path.

This is possible because movement of a satellite around the planet Earth is a good example of uniform circular motion, which is characterized by the movement of a body describing a circumference of a given radius with constant speed.

Therefore in this movement the velocity has a constant magnitude, but its direction varies continuously.

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The velocity of a sound wave in a straight line is 660 mph. The wave is moving with a constant velocity. It means that the change in velocity is equal to 0.

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3 years ago
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A jet fighter flies from the airbase A 300 km East to the point M. Then 350 km at 30° West of North.
It means : at 60° North of West. So the distance from the final point to the line AM is :
350 · cos 60° = 350 · 0.866 = 303.1 km
Let`s assume that there is a line N on AM.
AN = 125 km and NM = 175 km.
And finally jet fighter flies 150 km North to arrive at airbase B.
NB = 303.1 + 150 = 453.1 km
Then we can use the Pythagorean theorem.
d ( AB ) = √(453.1² + 125²) = √(205,299.61 + 15,625) = 470 km
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α = cos^(-1) 0.266 = 74.6°
90° - 74.6° = 15.4°
Answer: The distance between the airbase A and B is 470 km.
Direction is : 15.4° East from the North. 
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