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2 years ago

Select "Growth" or "Decay" to classify each function.

1 answer:

5 0

$y=c(a)^x\\\\if\ a > 0\ then\ "Growth"\\\\if\ 0 < a < 1\ then\ "Decay"\\-----------------------------\\y=200(0.5)^{2t}\to a=0.5 < 1-"Decay"\\\\y=\dfrac{1}{2}(2.5)^{\frac{t}{6}}\to a=2.5 > 1-"Growth"\\\\y=(0.65)^{\frac{t}{4}}\to a=0.65 < 1-"Decay"$

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The modulus of a real number, n, is equal to _____.

Bogdan [553]

Answer:

The absolute value

Step-by-step explanation:

we know that

The modulus of a real number, is equal to the absolute value of the real number

The modulus of a positive number is simply the number and the modulus of a negative number is found by ignoring the minus sign.

Then

modulus of n is always positive number .such that n belongs to real number R.

Modules of n is denoted by |n|

<u><em>Examples: </em></u>

|-4|=4

|2.5|=2.5

|-100.1|=100.1

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3 years ago

Another question, what is 94939423^2 have fun!

Bas_tet [7]

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2 years ago

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zhuklara [117]

The answer is 9. there are 9 different combinations to choose from.

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2 years ago

Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?

sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have $V=IR^{2}$ and let $H$ be the subset of $V$ of all points on the line

$4x+3y=12$

We need to find if $H$ is a subspace of the vector space $V$ .

In $IR^{2}$ all the possibilities for own subspace of the vector space $IR^{2}$ are :

$IR^{2}$ itself.

The vector $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$

All lines in $IR^{2}$ that passes through the origin ( $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$ )

We know that $H$ is the subset of $IR^{2}$ of all points on the line $4x+3y=12$

If we look at the equation, the point $\left[\begin{array}{c}0&0\end{array}\right]$ doesn't verify it because :

$4x+3y=12\\4(0)+3(0)=12\\0=12$

Which is an absurd. Therefore, $H$ doesn't contain the origin (and $H$ is a line in $IR^{2}$ ). Finally, it can't be a vector space of $V=IR^{2}$

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2 years ago

Can someone please help me ASAP

forsale [732]

Answer:

its B

Step-by-step explanation:

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3 years ago