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dezoksy [38]
3 years ago
11

Select "Growth" or "Decay" to classify each function.

Mathematics
1 answer:
frozen [14]3 years ago
5 0

y=c(a)^x\\\\if\ a > 0\ then\ "Growth"\\\\if\ 0 < a < 1\ then\ "Decay"\\-----------------------------\\y=200(0.5)^{2t}\to a=0.5 < 1-"Decay"\\\\y=\dfrac{1}{2}(2.5)^{\frac{t}{6}}\to a=2.5 > 1-"Growth"\\\\y=(0.65)^{\frac{t}{4}}\to a=0.65 < 1-"Decay"

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Please answer this question!!
Aloiza [94]
To find the surface area of the rectangular prism you do.

2(lw + lh + wh).

2((26*18) + (26*8) + (18*8))

2(468 + 208 + 144)

2* 820

the answer is 1640cm^2

8 0
3 years ago
I have 4 factors. Three of my factors are 1,2 and 10. What is my fourth factor?
Verdich [7]
The fourth factor is 20.
6 0
3 years ago
Read 2 more answers
What is the value of x?<br> 12 units<br> 18<br> 15 units<br> 20 units<br> 24 units
Ierofanga [76]

Answer:

Step-by-step explanation:

Question

What is the value of x?

12 units

Answer:

Step-by-step explanation:18

15 units

20 units

24 units

5 0
3 years ago
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What is the apr for a $585 tablet with 12 payments of $50.81
JulsSmile [24]

Answer:

the answer is 4%

Step-by-step explanation:

585/12=48.75

50.81-48.74=2.06

now 2.06 that's the money from interest rate

so now 2.06/50.81=0.04

so the answer is 4%

3 0
3 years ago
WILL MARK BRAINLIEST
Levart [38]

Answer:

Part 1:

The solution set of the system of equations is x = 1, y = 1

Part 2:

The solution set is x = 1, y = 1

Part 3:

The similarity of the system of equations in Parts 1 and 2 is that they have the same solution set

The difference of the system of equations in Parts 1 and 2 is that they are arranged differently

Step-by-step explanation:

Part 1:

The system of equation is given as follows;

2·x + y = 3...(1)

x = 2·y - 1...(2)

The above system of equations can be written in terms of the variable, y, as follows;

For equation (1), we have;

y = 3 - 2·x

For equation (2), we have;

y = (x + 1)/2

From the attached graph created with Microsoft Excel, we have;

The solution set (the point of intersection) of the system of equations is x = 1, y = 1

To accurately find the common solution, we have;

(x + 1)/2 = 3 - 2·x

x + 1 = 2·(3 - 2·x) = 6 - 4·x

x + 1 = 6 - 4·x

x + 4·x = 6 - 1

5·x = 5

x = 5/5 = 1

x = 1

Therefore, y = 3 - 2·x = 3 - 2× 1 = 1, at the common solution

Part 2:

y = -2x + 3

x - 2y = -1

∴ x = 2y -1

y = -2(2y -1) + 3

y = -4y + 2 + 3

5y = 5

y = 1

x = 2y - 1 = 2 - 1 = 1

x = 1

The solution set is x = 1, y = 1

Part 3

The system of equations are similar in terms of their solution

The system of equations are different in terms of their arrangement

6 0
2 years ago
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