calculate moles of both reagents given and the moles of FeS that each of them would form if they were in excess
moles = mass / molar mass
moles Fe = 7.62 g / 55.85 g/mol
= 0.1364 moles
1 mole Fe produces 1 mole FeS
Therefore 7.62 g Fe can form 0.1364 moles FeS
moles S = 8.67 g / 32.07 g/mol
= 0.2703 moles S
1 mole S can from 1 moles FeS
So 8.67 g S can produce 0.2703 moles FeS
The limiting reagent is the one that produces the least product. So Fe is limiting.
The maximum amount of FeS possible is from complete reaction of all the limiting reagent.
We have already determined that the Fe can form up to 0.1364 moles of FeS, so this is max amount of FeS you can get.
Convert to mass
hope this helps :)
Nuclear reactions are those that involve the nucleus of an atom. Nuclear fission involves the splitting of an atomic nucleus and the formation of two distinct atomic species. Nuclear fusion is indeed the combining of two atomic nuclei in order to form a single atomic species. Therefore the answer to the question is true.
Explanation: • Electronegativity is the tendency of an atom to attract the electrons in a bond towards it. • Ionization energy is the energy that should be given to a neutral atom to remove an electron from it. The difference in the electronegativity between the two elements is quite small, but the main reason for it is because chlorine is one period below oxygen. Chlorine’s valence electrons are thus less tightly bound than those of oxygen, so they would have lower first ionization energy. Does sodium or potassium have larger ionization energy?
Answer:
52.80 % is the percent yield of the reaction.
Explanation:
Mass of nitrogen gas = 38.0 g
Moles of nitrogen = 
According to reaction, 1 moles of nitrogen gas gives 2 moles of ammonia, then 2.235 moles of nitrogen will give:
ammonia
Mass of 4.470 moles of ammonia
= 4.470 mol × 17 g/mol = 75.99 g
Theoretical yield of ammonia = 217.8 g
Experimental yield of ammonia = 40.12 g
The percentage yield of reaction:
52.80 % is the percent yield of the reaction.
