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Anastaziya [24]
3 years ago
12

In terms of bonds what would the molecule C6H12 be classified as

Chemistry
1 answer:
docker41 [41]3 years ago
5 0

It has a double C=C bond so that means it's unsaturated, but it can also be a cyclic compound with only simple C-C bonds

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Draw the structure of a compound with the molecular formula CgH1002 that exhibits the following spectral data.
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Answer:

The answer you are looking for is A

7 0
4 years ago
The theory general relativity was discovered by who
svetoff [14.1K]
<span>The theory general relativity was discovered by Albert Einstein </span>
4 0
3 years ago
Consider the reaction given below.
Drupady [299]

Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

6 0
4 years ago
Name two control substance?
guapka [62]
The two control bases would be water and salt.
6 0
3 years ago
Read 2 more answers
8. True or False: There are some exceptions to the rule.... organisms such as a protist called a
ankoles [38]

There are some exceptions to the rule organisms such as a protist called a  euglena can be both heterotrophic and autotrophic. This is a true statement.

Explanation:

  • Euglena is a large genus of unicellular protists: they have both plant and animal characteristics
  • Photoautotrophs include protists that have chloroplasts, such as Spirogyra. Heterotrophs get their energy by consuming other organisms. Other protists can get their energy both from photosynthesis and from external energy sources
  • All live in water and move by means of a flag ellum. This is an animal characteristic. Most have chloroplasts, which are characteristic of algae and plants
  • Euglena is photosynthetic in the presence of sunlight i.e autotrophic, when deprived of sunlight they behave like heterotrophs by predating on other smaller organisms.
  • Most species of Euglena have photosynthesizing chloroplasts within the body of the cell, which enable them to feed by autotrophy, like plants. They can also take nourishment heterotrophically, like animals.

6 0
3 years ago
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