A helicopter is ascending vertically. a passenger accidentally drops her wallet out the sides of the helicopter when it is 160 m
1 answer:
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Answer:
Explanation:
Given:
- area of piston on the smaller side of hydraulic lift,
- area of piston on the larger side of hydraulic lift,
- Weight of the engine on the larger side,
Now, using Pascal's law which state that the pressure change in at any point in a confined continuum of an incompressible fluid is transmitted throughout the fluid at its each point.
is the required effort force.
Answer:
In parallel circuits all components have the same voltage. In series circuits all components have the same current.
Explanation:
Voltage in a circuit is akin to pressure in water, while current is akin to flow in water.
Voltage and current are related to resistance by Ohm's law:
Where:
V: voltage
I: current
R: resistance
In a parallel circuit all the terminals of one side of the devices are connected together. This is known as a node. Nodes have a certain voltage. Devices connected in parallel will have one node on each side, and each node will have it's own voltage. Current will flow through each component independently depending on their resistance, so it is not the same for all of them.
In a series circuit components are connected one after the other, the current that flows through one must continue and flow through the next, so they all have the same current. But since they might have different resistances they might have different voltage differences between their terminals.
Parallel connection is useful when you have devices that require a specific voltage, such as household appliances. All wall power outlets are connected in parallel.
Series connection is useful when you want to control current. When you use a LED you must be careful not to apply an overcurrent, so a series resistor is commonly used to limit the current.
Answer:
A) x and y components of the electric field (Ep) at the origin.
Epx = -1620.5 N/C
Epy = -1620.5 N/C
Ep = (1620.5(-i)+1620.5(-j)) N/C
B) Magnitude of the electric field (Ep) at the origin.
Ep= 2291.7 N/C
Explanation:
Conceptual analysis
The electric field at a point P due to a point charge is calculated as follows:
E = k*q/d²
E: Electric field in N/C
q: charge in Newtons (N)
k: electric constant in N*m²/C²
d: distance from charge q to point P in meters (m)
Equivalence
1nC= 10⁻⁹C
Data
K= 9x10⁹N*m²/C²
q₁ = q₂= +6.5nC=+6.5 *10⁻⁹C
d₁=d₂=0.190m
Graphic attached
The attached graph shows the field due to the charges:
Ep₁ : Electric Field at point P (x=0, y=0) due to charge q₁. As the charge q₁ is positive (q₁+) ,the field leaves the charge.
Ep₂: Electric Field at point P (x=0, y=0) due to charge q₂. As the charge q₂ is positive (q₂+) ,the field leaves the charge
Ep: Total field at point P due to charges q₁ and q₂.
Because q₁ = q₂ and d₁ = d₂, then, the magnitude of Ep₁ is equal to the magnitude of Ep₂
Ep₁ = Ep₂ = k*q/d² = 9*10⁹*6.5*10⁻⁹/0.190m² = 1620.5 N/C
Look at the attached graphic :
Epx = Ep₁= -1620.5 N/C
Epy = Ep₂= -1620.5 N/C
A) x and y components of the electric field (Ep) at the origin.
Ep = (1620.5(-i)+1620.5(-j)) N/C
B) Magnitude of the electric field (Ep) at the origin.
