Answer:
35.7 g
Kf - the cryoscopic constant of the solvent; b - the molality of the solution. So, the idea here is that you can only dissolve 35.7 g of sodium chloride, NaCl, in water at 0∘C.
Explanation:
The correct answer is C. I hope this helped!! :D
Answer:
See explanation
Explanation:
% optical purity = specific rotation of mixture/specific rotation of pure enantiomer * 100/1
specific rotation of mixture = 23°
specific rotation of pure enantiomer = 61°
Hence;
% optical purity = 23/61 * 100 = 38 %
More abundant enantiomer = 100% - 38 % = 62%
Hence the pure (S) carvone is (-) 62° is the more abundant enantiomer.
Enantiomeric excess = 62 - 50/50 * 100 = 24%
Hence
(R) - carvone = 38 %
(S) - carvone = 62%
First calculate the mole fraction of each substance:
Acetone: 2.88 mol ÷ (2.88 mol + 1.45 mol) = 0.665
Cyclohexane: 1.45 ÷ (2.88 mol + 1.45 mol) = 0.335
Raoult's Law: P(total) = P(acetone) · χ(acetone) + P(cyclohexane) · χ(cyclohexane).
P(total) = 229.5 torr · 0.665 + 97.6 torr · 0.335
P(total) = 185.3 torr
χ for acetone: 229.5 torr · 0.665 ÷ 185.3 torr = 0.823
χ for cyclohexane: 97.6 torr · 0.335 ÷ 185.3 torr = 0.177
The molecular formula shows the number of atoms present. The molecular formula of the gas is most likely ClO2.
In terms of gas density and molar mass, the ideal gas equation can be written in the form; PM = dRT
Where;
P = pressure of the gas
M = molar mass of the gas
d = density of the gas
R = molar gas constant
T = temperature of the gas
Making the molar mass of the gas the subject of the formula;
M = dRT/P
d = 2.875 g/L
R = 0.082 atmLmol-1K-1
T = 11°C + 273 = 284 K
P = 750.0 mm Hg or 0.99 atm
Substituting values;
M = 2.875 g/L × 0.082 atmLmol-1K-1 × 284 K/ 0.99 atm
M = 67.6 g/mol
The gas is most likely ClO2.
Learn more: brainly.com/question/11969651