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2 years ago

How many daltons is in an ion with 15 protons, 16 neutrons and 17 electrons?

1 answer:

8 0

31
A dalton is the same as an atomic mass unit. And an atomic mass unit is approximately the mass of a nucleon (proton or neutron) such that the mass is 1 g/mol. So in this problem you have 15 protons and 16 neutrons, so the number of daltons is 15 + 16 = 31.

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A city in Laguna generates 0.96 kg per capita per day of Municipal Solid Waste (MSW). Makati City in Metro Manila generates 1.9

mamaluj [8]

Answer:

i) amount of MSW generated:

Laguna: 19200 Kg/day

Makati: 38000 Kg/day

ii) number of trucks to collect twice weekly:

Laguna: 3 trucks

Makati: 5 trucks

iii) volume of MSW in tons that enter landfill/week:

Laguna: 147.84 ton/week

Makati: 292 ton/week

Explanation:

i) Laguna: 0.96 Kg person / day of MSW * 20000 = 19200 Kg MSW / day

⇒ Laguna: 19200 Kg/day * ( 7day/ week ) = 134400 Kg/week

Makati: 1.9 Kg person / day of MSW * 20000 = 38000 Kg MSW / day

⇒ Makati: 38000 Kg/day * ( 7day/week ) = 266000 Kg/week

ii) truck capacity = 4.4 ton * ( Kg / 0.0011 ton ) = 4000 Kg

⇒ quote/day = 4000 Kg * 0.75 = 3000 Kg

⇒ loads/day = 2 * 3000 kg = 6000 Kg

⇒ operate/week = 5 * 6000 Kg = 30000 Kg

∴ Laguna: number of trucks needed/week= 134400 / 30000 = 4.48 ≅ 5 trucks

⇒ number of trucks to collect twice weekly = 5 / 2 = 2.5 ≅ 3 trucks

∴ Makati : number of trucks needed/week = 266000 / 30000 = 8.86 ≅ 9 trucks

⇒ number of trucks to collect twice weekly = 9 / 2 = 4.5 ≅ 5 trucks

iii) enter landfill/week:

Laguna: 134400Kg MSW/week * ( 0.0011 ton/Kg ) = 147.84 ton/week

Makati: 266000Kg MSW/week * ( 0.0011 ton/Kg ) = 292 ton/week

4 0

2 years ago

What is the difference between heterozygous and homozygous?

Yuri [45]

we can differentiate a heterozygous individual from a homozygote by analyzing their alleles. If the alleles in the homologous chromosomes are the same, we say that it is a homozygote. If the alleles are different, the individual is heterozygous.

5 0

3 years ago

What is the number of molecules of c2h5oh in a 3m solution that contains 4.00kg h2o?

Veronika [31]

The number of C2H5OH in a 3 m solution that contain 4.00kg H2O is calculate as below

M = moles of the solute/Kg of water

that is 3M = moles of solute/ 4 Kg
multiply both side by 4

moles of the solute is therefore = 12 moles

by use of Avogadro law constant

1 mole =6.02 x10^23 molecules

what about 12 moles

=12 moles/1 moles x 6.02 x10^23 = 7.224 x10^24 molecules

3 0

3 years ago

If the vapor pressure of ethanol at 34.7degree C is 100

saw5 [17]

Answer:

we will use the Clausius-Clapeyron equation to estimate the vapour pressures of the boiling ethanol at sea level pressure of 760mmHg:

ln (P2/P1) = $\frac{ΔvapH}{R}([tex]\frac{1}{T1}$ - $\frac{1}{T2}$ )

where

P1 and P2 are the vapour pressures at temperatures T1 and T2

Δ vapH = the enthalpy of vaporization of the ETHANOL

R = the Universal Gas Constant

In this problem,

P 1 = 100 mmHg

; T 1 = 34.7 °C = 307.07 K

P 2 = 760mmHg

T 2 =T⁻²=?

Δ vap H = 38.6 kJ/mol

R = 0.008314 kJ⋅K -1 mol -1

ln ( 760/10)=(0.00325 - T⁻²) (38.6kJ⋅mol-1 /0.008314 )

0.0004368=(0.00325 - T⁻²)

T⁻²=0.002813

T² = 355.47K

6 0

3 years ago

The ages of rocks that contain fossils can be determined using the isotope 87Rb. This isotope of rubidium undergoes beta

AVprozaik [17]

Answer:

Age of rock = 722 million years old

Explanation:

Using the formula; <em>fraction remaining = 0.5ⁿ</em>

where n = number of half lives elapsed.

However, from the given values, fraction remaining = 1.000 - 0.0105

fraction remaining = 0.9895

Substituting in the formula to determine the number of half-lives:

0.9895 = 0.5ⁿ

log 0.9895 = n log 0.5

-0.0045842 = -0.30103 n

number of half lives elapsed, n = 0.0152

Therefore age of rock = 0.0152 x 4.75 x 10¹⁰ years = 7.22 x10⁸ years

Age of rock = 722 million years old

7 0

2 years ago