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choli [55]
3 years ago
13

How many daltons is in an ion with 15 protons, 16 neutrons and 17 electrons?

Chemistry
1 answer:
Vera_Pavlovna [14]3 years ago
8 0
31  
A dalton is the same as an atomic mass unit. And an atomic mass unit is approximately the mass of a nucleon (proton or neutron) such that the mass is 1 g/mol. So in this problem you have 15 protons and 16 neutrons, so the number of daltons is 15 + 16 = 31.
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An atom gets over all positive charge by ____ _______
Rasek [7]
<h2>Answer:</h2>

Nucleus.

<h2>Explanation:</h2>
  • In an atom the nucleus has an overall positive charge as it contains the protons.
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Result: Nucleus is the overall positive charge of an atom.

4 0
3 years ago
2. Explain why sedimentary rock layers of the North and South Rim(side) of the Grand Canyon are the same age, using Steno’s Prin
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Answer:

Law of Lateral Continuity The Grand Canyon.

and

he same rock layers on opposite sides of the canyon. The matching rock layers were deposited at the same time, so they are the same age.

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3 years ago
How much 6.0 m hno3 is needed to neutralize 39ml of 2 m koh
Sever21 [200]

Answer:

13mL

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

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Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

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Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

6 x Va / 2 x 39 = 1/1

Cross multiply to express in linear form

6 x Va = 2 x 39

Divide both side by 6

Va = (2 x 39)/6

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5 0
3 years ago
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algol [13]

Answer:

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Explanation:

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6 0
3 years ago
Wha twill form an acidic solution in water?
Mariulka [41]

Answer:

A strong acid

Any strong acid (such as HCl, HBr, or HNO_{3}) will completely dissociate forming a very weak conjugate base and H3O which will be acidic.

8 0
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