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Zepler [3.9K]
3 years ago
12

Diagnostic ultrasound of frequency 4.80 MHz is used to examine tumors in soft tissue.

Physics
1 answer:
Tems11 [23]3 years ago
6 0

Answer:

0.0000714583 m

0.0003125 m

Explanation:

v = Speed of sound in the medium

f = Frequency = 4.8 MHz

Wavelength is given by

\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{343}{4.8\times 10^6}\\\Rightarrow \lambda=0.0000714583\ m

Wavelength of the sound in air is 0.0000714583 m

\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{1500}{4.8\times 10^6}\\\Rightarrow \lambda=0.0003125\ m

Wavelength of the sound in the tissue is 0.0003125 m

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1. Kinetic

He makes the ball move by kicking it, which increases the kinetic energy

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3 years ago
An electromagnetic wave has a frequency of 5.0 x 1014 Hz. What is the
andrezito [222]

Answer:

c

Explanation:

wavelength = speed of light/ frequency

= (3x 10^8 m/s)/(5.0 x 10^14 Hz)

= 6.0 x 10^-7 m

5 0
3 years ago
A bell rings at a frequency of 75hz on a warm 25 degree evening. calculate the...
allochka39001 [22]

Answer:

Explanation:

We need 2 different equations for this problem: first the velocity of sound equation, then the frequency of the sound equation.

The velocity of sound is found in:

v = 331.5 + .606T

We need to find that first in order to fill it into the frequency equation which is

f=\frac{v}{\lambda} where v is the velocity we will find the part a, f is frequency and lambda is the wavelength. Starting with the velocity of the sound:

v = 331.5 + .606(25) and

v = 331.5 + 15 and rounding correctly using the rules for sig fig when adding:

v = 347 m/s

Filling that into the frequency equation:

75=\frac{347}{\lambda} and

\lambda=\frac{347}{75} so

\lambda=4.6m

7 0
3 years ago
2. A car accelerates uniformly from +10.0 m/s to +50.0 m/s over a distance of 225 m. How long did it take to go that distance? S
artcher [175]
Let's call the constant acceleration a.
At a time t, its speed will thus be v(t)=a*t+v0 where v0 is its initial speed, here 10 m/s. Hence v(t)=a*t+10.

From there we can deduce the position P(t)=a*t^2/2+10t+p0 where p0 is the initial position, here 0.

Hence P(t)=a*t^2/2+10t

Let's call T the time at which it's at 50 m/s, we know that P(T)=225m and that v(T)=50 m/s hence a*T+10=50 thus a=40/T and P(T)=(40/2+10)T=30T

Hence T=225/30=7.5

It took 7.5 seconds


7 0
3 years ago
If a force of 10 N acts on an object and an additional force of 6 N acts on the object in
PIT_PIT [208]

Answer:

D

Explanation:

For this kind of problem, forces add. F = F1 + F2

F1 = 6 N

F2 = 10 N

F = 6N + 10N

F = 16N

6 0
3 years ago
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