Answer:
The pressure exerted by the girl is 245,000 N/m²
Explanation:
Given;
mass of the girl, m = 50 kg
area of the girl's shoe, A = 0.002 m²
The pressure exerted by the girl is calculated as follows;
Therefore, the pressure exerted by the girl is 245,000 N/m²
A) produces offspring with variations
The pendulum movement is a famous situation manifesting the force of tension by the rope and the force of gravity coming into play. There are already derived equations explaining the behavior of the pendulum movement.
Period = t = 2π√(L/g)
Since, we don't have exact values for the parameters, let's just find the ratio to provide comparison. Let's find the ratio of the pendulum on the moon (t,moon) to the period of the pendulum on earth (t,earth).
t,moon/t,earth = 2π√(L/g/6) ÷ 2π√(L/g) = √6
Therefore, the period of the pendulum on the moon is the square root of 6 times that of in the earth.
Answer:
a) x_{cm} = m₂/ (m₁ + m₂) d
, b) x_{cm} = 52.97 pm
Explanation:
The expression for the center of mass is
= 1 / M ∑
Where M is the total masses, mI and xi are the mass and position of each element of the system.
Let's fix our reference system on the oxygen atom and the molecule aligned on the x-axis, let's use index 1 for oxygen and index 2 for carbon
x_{cm} = 1 / (m₁ + m₂) (0+ m₂ x₂)
Let's reduce the magnitudes to the SI system
m₁ = 17 u = 17 1,661 10⁻²⁷ kg = 28,237 10⁻²⁷ kg
m₂ = 12 u = 12 1,661 10⁻²⁷ kg = 19,932 10⁻²⁷ kg
d = 128 pm = 128 10⁻¹² m
The equation for the center of mass is
x_{cm} = m₂/ (m₁ + m₂) d
b) let's calculate the value
x_{cm} = 19.932 10⁻²⁷ /(19.932+ 28.237) 10⁻²⁷ 128 10-12
x_{cm} = 52.97 10⁻¹² m
x_{cm} = 52.97 pm