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harina [27]
4 years ago
10

Megan is waiting for the school bus. She sees it driving down the street straight toward her position. If the bus is moving at a

constant speed, which graph shows the position of the bus relative to Megan through time?
Physics
2 answers:
Maksim231197 [3]4 years ago
4 0

Answer:

Explanation:

Is megan like going to be ran over the question doesn't have enoght info

love history [14]4 years ago
4 0

Answer:

the answer is W

Explanation:

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
Tasya [4]

Answer:

98 N

Explanation:

The weight of an object is given by:

W=mg

where

m is the mass of the object

g=9.8 m/s^2 is the acceleration due to gravity

In this problem, the mass of the lemur is m=10 kg, so its weight is

W=mg=(10 kg)(9.8 m/s^2)=98 N

3 0
3 years ago
Alex swims at an average speed of 4.5 m/s how far does he swim in one minute 24 seconds
Zepler [3.9K]

Answer:

378

Explanation:

60 seconds in one minute

add the 24 seconds

multiply it by 4.5

60 + 24 = 84

4.5 x 84 = 378

8 0
3 years ago
How is a full moon different from a new moon?
koban [17]
<span>A full moon is at its brightest, and here is no disk to be seen. New moons are barely visable.</span>
8 0
3 years ago
Read 2 more answers
A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.
kodGreya [7K]

Answer:

The  z-component of the force is  \= F_z  =  0.00141 \ N    

Explanation:

From the question we are told that

          The charge on the particle is q =  7.76 *0^{-8} \  C    

           The magnitude of the magnetic field is  B =  0.700\r i \ T

            The  velocity of the particle toward the x-direction is  v_x  =  -1.68*10^{4}\r  i  \ m/s

           The  velocity of the particle toward the y-direction is

v_y  =  -2.61*10^{4}\ \r j  \ m/s

           The  velocity of the particle toward the z-direction is

v_y  =  -5.85*10^{4}\ \r k  \ m/s

Generally the force on this particle is mathematically represented as

          \= F  =  q (\= v   X  \= B )

So  we have    

          \= F  =  q ( v_x \r  i + v_y \r  j  +  v_z \r k  )  \ \ X \ (  \= B i)

         \= F  = q (v_y B(-\r  k) + v_z B\r j)      

  substituting values

       \= F  = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r  z) + [(5.58*10^{4}) (0.700)]\r y)    

      \= F=  0.00303\ \r j +0.00141\ \r k                  

So the z-component of the force is  \= F_z  =  0.00141 \ N    

Note :  The  cross-multiplication template of unit vectors is  shown on the first uploaded image  ( From Wikibooks ).

7 0
3 years ago
Urgent help for a physics exercise!
Zigmanuir [339]

a)

Amplitude of wave is given as maximum displacement from mean position

So here amplitude is 1.25 cm

b)

Wavelength is the length of the wave that it travels in one time period

From graph we can say the wavelength is given as 3cm

PART C)

Time period of wave is the time after which it repeats its shape

Speed of the wave = 21 cm/s

time period = wavelength / speed

T = \frac{3}{21}

T = \frac{1}{7} s

Now frequency is

f = \frac{1}{T}

f = 7 Hz

PART D)

Time period = \frac{1}{f}[/tex]

T = 0.143 s

6 0
4 years ago
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