Given:
Consider the below figure attached with this question.
To find:
The perimeter of the polygon UVWXYZ.
Solution:
All sides and vertical and horizontal. So, we can easily find the side lengths of the given polygon by counting the boxes between two points.
From the figure it is clear that,
UV = 9 units
VW = 2 units
WX = 3 units
XY = 3 units
YZ = 6 units
ZU = 5 units
Now, perimeter is the sum of all the sides.



Therefore, the perimeter of UVWXYZ is 28 units.
The solution is -0.609611 and -1.64, I do not think you can simply find this by factoring but the only way is graphing it
Answer:
From the sum of angles on a straight line, given that the rotation of each triangle attached to the sides of the octagon is 45° as they move round the perimeter of the octagon, the angle a which is supplementary to the angle turned by the triangles must be 135 degrees
Step-by-step explanation:
Given that the triangles are eight in number we have;
1) (To simplify), we consider the five triangles on the left portion of the figure, starting from the bottom-most triangle which is inverted upside down
2) We note that to get to the topmost triangle which is upright , we count four triangles, which is four turns
3) Since the bottom-most triangle is upside down and the topmost triangle, we have made a turn of 180° to go from bottom to top
4) Therefore, the angle of each of the four turns we turned = 180°/4 = 45°
5) When we extend the side of the octagon that bounds the bottom-most triangle to the left to form a straight line, we see the 45° which is the angle formed between the base of the next triangle on the left and the straight line we drew
6) Knowing that the angles on a straight line sum to 180° we get interior angle in between the base of the next triangle on the left referred to above and the base of the bottom-most triangle as 180° - 45° = 135°.