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avanturin [10]
2 years ago
15

Number of moles in 31.99g O2 And 176.8g NaCl

Chemistry
1 answer:
sergey [27]2 years ago
8 0

#O_2

\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}

\\ \sf\longmapsto No\:of\:moles=\dfrac{31.99}{32}

\\ \sf\longmapsto No\:of\:moles\approx 1

#NaCl

\\ \sf\longmapsto No\:of\:moles=\dfrac{176.8}{58.5}

\\ \sf\longmapsto No\;of\:moles=3mol

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Answer:

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When the enthalpy of the reaction is provided, it is always in the context of moles; i.e., ΔHrxn=+252.8 kJ when two moles of CH3
Morgarella [4.7K]

<u>Answer:</u> The balanced chemical equation is written below.

<u>Explanation:</u>

There are 2 types of chemical reaction classified on the basis of heat change:

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We are given:

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3 years ago
A pycnometer is a precisely weighted vessel that is used for highly accurate density determinations. Suppose that a pycnometer h
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5.758  is the density of the metal ingot in grams per cubic centimeter.

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Density of water at 20 °C = d =998.2 kg/m^3

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1 m^3=10^6 cm^3

998.2 kg/m^3=\frac{998.2 \times 1000 g}{10^6 cm^3}=0.9982 g/cm^3

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V=\frac{m'}{d}=\frac{18.05 g}{0.9982 g/cm^3}=18.08 cm^3

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Mass of water when metal and water are together ,m''= 56.83 g - M'- M

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Volume of water when metal and water are together = v

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Since volume cannot be in negative .

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