Question

Number of moles in 31.99g O2 And 176.8g NaCl

Answer 1

#O_2

$\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}$

$\\ \sf\longmapsto No\:of\:moles=\dfrac{31.99}{32}$

$\\ \sf\longmapsto No\:of\:moles\approx 1$

#NaCl

$\\ \sf\longmapsto No\:of\:moles=\dfrac{176.8}{58.5}$

$\\ \sf\longmapsto No\;of\:moles=3mol$